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3 years ago

What is the term for the disturbed water left behind as a boat moves through the water?

Physics

2 answers:

marusya05 [52]3 years ago

7 0

The term for the disturbed water left behind as a boat moves through the water is wake.
When a boat glides through any type of water, it will sort of separate the water behind it for a few seconds, after which the water will return to normal once again. I've attached the image so that you can see clearly what I'm talking about.

saveliy_v [14]3 years ago

3 0

Answer:

Wake

Explanation:

As a boat moves through a water body (sea, river or ocean), the propeller causes the water to be separated as the boat moves. This separated water forms a new pattern based on the disturbance conferred by the boat. The disturbed water forms a visible huge flow of water sideways and backwards (based on the speed, size and weight of the boat). This disturbed water is referred to as the wake of the boat.

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Read 2 more answers

A steel pipe of 12-in. outer diameter is fabricated from 1 4 -in.-thick plate by welding along a helix that forms an angle of 25

Varvara68 [4.7K]

Answer:

Normal stress = 66/62.84 = 1.05kips/in²

shearing stress = T/2 = 0.952/2 = 0.476 kips/in²

Explanation:

A steel pipe of 12-in. outer diameter d₂ =12in d₁= 12 -4in = 8in

4 -in.-thick

angle of 25°

Axial force P = 66 kip axial force

determine the normal and shearing stresses

Normal stress б = force/area = P/A

= 66/ (П* (d₂²-d₁²)/4

=66/ (3.142* (12²-8²)/4

= 66/62.84 = 1.05kips/in²

Tangential stress T = force* cos ∅/area = P/A

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=59.82/ (3.142* (12²-8²)/4

= 59.82/62.84 = 0.952kips/in²

shearing stress = tangential stress /2

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3 years ago

Consider two children sitting on a merry-go-round, with one closer to the outer edge and one closer to the center. show answer N

dolphi86 [110]

Answer:

They both have the same angular speed.

Explanation:

The mathematical formula for angular speed is:

$w=\frac{2\pi}{T}$

where $w$ is angular speed, $2\pi$ is a constant, and $T$ is the period (the time it takes the marry-go-round to complete a lap).

What we can see from the formula is that, since the $2\pi$ does not change its value, the angular speed depends only on the period T.

In this case for both the children closer to the outher edge and for the children closer to the center, the time to complete a lap is the same, because the time does not depend on where they are sitting in the marry go round. This means that the period for both is the same.

Thus, since the period for both is the same, the angular speed given by

$w=\frac{2\pi}{T}$ will also be the same

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4 years ago

A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it st

jeka57 [31]

Answer:

The magnitude of change in momentum is (2mv).

Explanation:

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Let the mass of ball is m. A tennis player smashes a ball of mass m horizontally at a vertical wall. The ball rebounds at the same speed v with which it struck the wall.

Initial speed of the ball is v and final speed, when it rebounds, is (-v). The change in momentum is given by :

p = final momentum - initial momentum

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So, the magnitude of change in momentum is (2mv).

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3 years ago