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Anuta_ua [19.1K]
3 years ago
13

What is the term for the disturbed water left behind as a boat moves through the water?

Physics
2 answers:
marusya05 [52]3 years ago
7 0
The term for the disturbed water left behind as a boat moves through the water is wake.
When a boat glides through any type of water, it will sort of separate the water behind it for a few seconds, after which the water will return to normal once again. I've attached the image so that you can see clearly what I'm talking about. 

saveliy_v [14]3 years ago
3 0

Answer:

Wake

Explanation:

As a boat moves through a water body (sea, river or ocean), the propeller causes the water to be separated as the boat moves. This separated water forms a new pattern based on the disturbance conferred by the boat. The disturbed water forms a visible huge flow of water sideways and backwards (based on the speed, size and weight of the boat). This disturbed water is referred to as the wake of the boat.    

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Answer:

3.64×10⁸ m

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Explanation:

Let's define some variables:

M₁ = mass of the Earth

r₁ = r = distance from the Earth's center

M₂ = mass of the moon

r₂ = d − r = distance from the moon's center

d = distance between the Earth and the moon

When the gravitational fields become equal:

GM₁m / r₁² = GM₂m / r₂²

M₁ / r₁² = M₂ / r₂²

M₁ / r² = M₂ / (d − r)²

M₁ / r² = M₂ / (d² − 2dr + r²)

M₁ (d² − 2dr + r²) = M₂ r²

M₁d² − 2dM₁ r + M₁ r² = M₂ r²

M₁d² − 2dM₁ r + (M₁ − M₂) r² = 0

d² − 2d r + (1 − M₂/M₁) r² = 0

Solving with quadratic formula:

r = [ 2d ± √(4d² − 4 (1 − M₂/M₁) d²) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(1 − (1 − M₂/M₁)) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(1 − 1 + M₂/M₁) ] / 2 (1 − M₂/M₁)

r = [ 2d ± 2d√(M₂/M₁) ] / 2 (1 − M₂/M₁)

When we plug in the values, we get:

r = 3.64×10⁸ m

If the moon wasn't there, the acceleration due to Earth's gravity would be:

g = GM / r²

g = (6.672×10⁻¹¹ N m²/kg²) (5.98×10²⁴ kg) / (3.64×10⁸ m)²

g = 3.34×10⁻³ m/s²

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The resultant vector is 11√2 km due north east.

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