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Veronika [31]
3 years ago
7

Which law states that there is a relationship between force, mass, and acceleration?

Physics
2 answers:
shepuryov [24]3 years ago
5 0
F=ma is Newton's 2nd law of motion
inysia [295]3 years ago
4 0
<span>Force is mass times acceleration, or F= m x a. This means an object with a larger mass needs a stronger force to be moved along at the same acceleration as an object with a small mass. </span>
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Mark each of the following statementsas true or false. If a statement refers to "two objects"interacting via some force, you are
slega [8]

Answer:

Explanation:

A,D,E

8 0
3 years ago
One timing problem in using fiscal policy to counter a recession is the "legislative lag" that occurs between the
natta225 [31]

<span>One timing problem in using fiscal policy to counter a recession is called the “legislative lag” it occurs between the time the time the need for fiscal action is recognized and between the time that it is taken in action.</span>

4 0
3 years ago
A catamaran with a mass of 5.44×10^3 kg is moving at 12 knots. How much work is required to increase the speed to 16 knots? (One
Andre45 [30]

The work that is required to increase the speed to 16 knots is 14,176.47 Joules

If a catamaran with a mass of 5.44×10^3 kg is moving at 12 knots, hence;

5.44×10^3 kg = 12 knots

For an increased speed to 16knots, we will have:

x = 16knots

Divide both expressions

\frac{5.44 \times 10^3}{x} = \frac{12}{16}\\12x = 16 \times 5.44 \times 10^3\\x = 7.23\times 10^3kg\\

To get the required work done, we will divide the mass by the speed of one knot to have:

w=\frac{7230}{0.51}\\w= 14,176.47Joules

Hence the work that is required to increase the speed to 16 knots is 14,176.47 Joules

Learn more here: brainly.com/question/25573786

8 0
3 years ago
In an RC circuit, what fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for
4vir4ik [10]

Answer:

The  fraction fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for 3.0 time constants is  

      k  = 0.903

Explanation:

From the question we are told that

     The time  constant  \tau  =  3

The potential across the capacitor can be mathematically represented as

     V  =  V_o  (1 -  e^{- \tau})

Where V_o is the voltage of the capacitor when it is fully charged

    So   at  \tau  =  3

     V  =  V_o  (1 -  e^{- 3})

     V  =  0.950213 V_o

   Generally energy stored in a capacitor is mathematically represented as

             E = \frac{1}{2 } * C  * V ^2

In this equation the energy stored is directly proportional to the the square of the potential across the capacitor

Now  since capacitance is  constant  at  \tau  =  3

        The  energy stored can be evaluated at as

         V^2 =  (0.950213 V_o )^2

       V^2 =  0.903  V_o ^2

Hence the fraction of the energy stored in an initially uncharged capacitor is  

      k  = 0.903

4 0
3 years ago
Which of the following consists of several billion stars and interstellar matter?
zloy xaker [14]
The answer is galaxy
4 0
3 years ago
Read 2 more answers
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