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KonstantinChe [14]
3 years ago
12

A female bear leaves her bear cubs in their den to go out in search of food. She travels one mile in 30 minutes, heading east. S

he travels quickly at first, but then she becomes tired and begins moving more slowly. She finds no food, so she then heads north for another 10 minutes. She finds a river so she is able to catch a few fish for her bear cubs. She then turns around and heads back toward her den. She travels southwest and returns home to feed her cubs.
Identify and describe all points of acceleration in the scenario about the bear and her cubs.
Make sure to explain why each example is a point of acceleration.
Chemistry
1 answer:
Vinil7 [7]3 years ago
8 0

Answer:

Points of acceleration:

1. When female bear goes quickly

2. After becoming tired, when she becomes slow

3. When she changes direction from east to north

4.When she slows down when she reaches the river bed

5. When she turns around

6.When she increases speed to travel southwest to return home

7. When she comes to a stop at home

Explanation:

1. When she is going quickly she is increasing her velocity thus positively accelerating

2. When she becomes slow, she is having negative acceleration.

3. When there is a change in direction of velocity there is an acceleration.

4. Again negative acceleration when she comes to a stop at the river bed

5. Turning around to the southwest direction requires acceleration

6. To increase the velocity to reach home, positive acceleration

7. To decrease the velocity to stop upon reaching home, negative acceleration

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WILL MARK BRANILEST
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Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

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B

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2 years ago
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