Answer:
A = 2 cm
, λ = 8 cm
Explanation:
The amplitude of a wave is the maximum height it has, in this case the height is measured by the vertical ruler,
We are told the balance point is in the reading of 5 cm, that the maximum reading is 3 cm and the Minimum reading is 7 cm. Therefore, the distance from the ends of the ridge to the point of equilibrium is
d = 7-5 = 2 cm
d = 5-3 = 2 cm
A = 2 cm
The wavelength is the minimum horizontal distance for which the wave is repeated, that is measured by the horizontal ruler.
The initial reading for 4 cm and the final reading for 8 cm, this distance corresponds to a crest of the wave, the complete wave is formed by two crests whereby the wavelength is twice this value
Δx = 8-4 = 4 cm
λ = 2 Δx
λ = 8 cm
Answer:
= 3.36 mm
Explanation:
From Ohm's law,
(Voltage = Current * Resistance)
![R = \dfrac{V}{I}](https://tex.z-dn.net/?f=R%20%3D%20%5Cdfrac%7BV%7D%7BI%7D)
The geometric definition of resistance is
![R = \rho\dfrac{l}{A}](https://tex.z-dn.net/?f=R%20%3D%20%5Crho%5Cdfrac%7Bl%7D%7BA%7D)
where
is the resistivity of the material,
and
are the length and cross-sectional area, respectively.
![A = \rho\dfrac{l}{R}](https://tex.z-dn.net/?f=A%20%3D%20%5Crho%5Cdfrac%7Bl%7D%7BR%7D)
![A = \rho\dfrac{l\timesI}{V}](https://tex.z-dn.net/?f=A%20%3D%20%5Crho%5Cdfrac%7Bl%5CtimesI%7D%7BV%7D)
Since the wire is assumed to have a circular cross-section, its area is given by
where
is the diameter.
![\pi\dfrac{d^2}{4} = \rho\dfrac{l\timesI}{V}](https://tex.z-dn.net/?f=%5Cpi%5Cdfrac%7Bd%5E2%7D%7B4%7D%20%3D%20%5Crho%5Cdfrac%7Bl%5CtimesI%7D%7BV%7D)
![d = \sqrt{\dfrac{4\rho l I}{\pi\times V}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%5Cdfrac%7B4%5Crho%20l%20I%7D%7B%5Cpi%5Ctimes%20V%7D%7D)
Resistivity of copper =
. With these and other given values,
![d = \sqrt{\dfrac{4\times1.68\times10^{-8}\times1.5\times290}{3.14\times 0.55}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%5Cdfrac%7B4%5Ctimes1.68%5Ctimes10%5E%7B-8%7D%5Ctimes1.5%5Ctimes290%7D%7B3.14%5Ctimes%200.55%7D%7D)
![d = \sqrt{1128.43\times10^{-8}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B1128.43%5Ctimes10%5E%7B-8%7D%7D)
![d = 33.6\times10^{-4} \text{ m}](https://tex.z-dn.net/?f=d%20%3D%2033.6%5Ctimes10%5E%7B-4%7D%20%5Ctext%7B%20m%7D)
<h3><u>Answer</u>;</h3>
1600 years
<h3><u>Explanation</u>;</h3>
- Half life is the time taken for a radioactive isotope to decay by half of its original amount.
- We can use the formula; N = O × (1/2)^n ; where N is the new mass, O is the original amount and n is the number of half lives.
- A sample of radium-226 takes 3200 years to decay to 1/4 of its original amount.
Therefore;
<em>1/4 = 1 × (1/2)^n</em>
<em>1/4 = (1/2)^n </em>
<em>n = 2 </em>
Thus; <em>3200 years is equivalent to 2 half lives.</em>
<em>Hence, the half life of radium-226 is 1600 years</em>
Answer:
V = 20.5 m/s
Explanation:
Given,
The mass of the cart, m = 6 Kg
The initial speed of the cart, u = 4 m/s
The acceleration of the cart, a = 0.5 m/s²
The time interval of the cart, t = 30 s
The final velocity of the cart is given by the first equation of motion
v = u + at
= 4 + (0.5 x 30)
= 19 m/s
Hence the final velocity of cart at 30 seconds is, v = 19 m/s
The speed of the cart at the end of 3 seconds
V = 19 + (0.5 x 3)
= 20.5 m/s
Hence, the final velocity of the cart at the end of this 3.0 second interval is, V = 20.5 m/s
Answer:
a) The proton's speed is 5.75x10⁵ m/s.
b) The kinetic energy of the proton is 1723 eV.
Explanation:
a) The proton's speed can be calculated with the Lorentz force equation:
(1)
Where:
F: is the force = 9.14x10⁻¹⁷ N
q: is the charge of the particle (proton) = 1.602x10⁻¹⁹ C
v: is the proton's speed =?
B: is the magnetic field = 3.28 mT
θ: is the angle between the proton's speed and the magnetic field = 17.6°
By solving equation (1) for v we have:
![v = \frac{F}{qBsin(\theta)} = \frac{9.14 \cdot 10^{-17} N}{1.602\cdot 10^{-19} C*3.28 \cdot 10^{-3} T*sin(17.6)} = 5.75 \cdot 10^{5} m/s](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7BF%7D%7BqBsin%28%5Ctheta%29%7D%20%3D%20%5Cfrac%7B9.14%20%5Ccdot%2010%5E%7B-17%7D%20N%7D%7B1.602%5Ccdot%2010%5E%7B-19%7D%20C%2A3.28%20%5Ccdot%2010%5E%7B-3%7D%20T%2Asin%2817.6%29%7D%20%3D%205.75%20%5Ccdot%2010%5E%7B5%7D%20m%2Fs)
Hence, the proton's speed is 5.75x10⁵ m/s.
b) Its kinetic energy (K) is given by:
![K = \frac{1}{2}mv^{2}](https://tex.z-dn.net/?f=%20K%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E%7B2%7D%20)
Where:
m: is the mass of the proton = 1.67x10⁻²⁷ kg
Therefore, the kinetic energy of the proton is 1723 eV.
I hope it helps you!