The work done in lifting an object to a height of 2 m is equal to two times the weight of the object. W = 2×mg
<h3>
Explanation:</h3>
Consider the mass of object to be m kg. The amount of work done to lift an object depends on the force required and the distance to which force is applied. To lift the object to a height of 2 m; Let F be the amount of force applied.
..................(1)
Where,
W=Work done
F= Amount of applied force
h=Height to which object is to be lifted
Applied force is equal to the weight of the object. Therefore,
..............(2)
Where,
m=Mass of the object
g=gravitational acceleration
Substituting (2) in (1), we get
For height = 2 m,
The work done in lifting an object to a height of 2 m is equal to twice the weight of the object.
Mechanical energy = potential energy + kinetic energy
The ball is on the ground so it has no potential energy. that's all i know.
Answer:
Final speed, v = 28.81 m/s
Explanation:
Given that,
Mass of the car, m = 1423 kg
Initial speed of the car, u = 26.4 m/s
Force experience by the car, F = 901 N
Distance, d = 106 m
To find,
The speed of the car after traveling this distance.
Solution,
The force experienced by a car is equal to the product of mass and acceleration.
Let v is the final speed of the car. Using third equation of motion to find it as :
v = 28.81 m/s
So, the final speed of the car is 28.81 m/s.