Question

It takes 338. kJ/mol to break an carbon-chlorine single bond. Cal broken by absorbing a single photon Iculate the maximum wavelength of light for which an carbon-chiorine single bond could be Round your answer to 3 significant digits

Answer 1

Answer:

354 nm

Explanation:

$E=\frac{h\times c}{\lambda}$

Where,  

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength of the light

So,  Given that:- Energy = 338. kJ/mol = 338000 J/mol

Also, $N_a=6.023\times 10^{23}\ {mol}^{-1}$

So, Energy for single photon = $\frac{338000}{6.023\times 10^{23}}\ J$

Applying the values in the above equation as:-

$\frac{338000}{6.023\times 10^{23}}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{\lambda}$

$69\times \:10^{26}\lambda=5^{20}\times \:62770482.511$

$\lambda=354\times 10^{-9}\ m=354\ nm$