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Lena [83]
3 years ago
13

SO2(g) + NO2(g) ↔ SO3(g) + NO(g) Kc = 0.33 A reaction mixture contains 0.41 M SO2, 0.14 M NO2, 0.12 M SO3 and 0.14 M NO. Which o

f the following statements is TRUE concerning this system?The reaction will shift in the direction of products.The reaction will shift in the direction of reactants.The reaction quotient will decrease.The equilibrium constant will decrease.The system is at equilibrium.
Chemistry
1 answer:
stepladder [879]3 years ago
8 0

Answer:

The reaction will shift in the direction of products.

Explanation:

<u>Step 1:</u> Data given

A reaction mixture contains:

0.41 M SO2

0.14 M NO2

0.12 M SO3

0.14 M NO

<u>Step 2:</u> The balanced equation

O2(g) + NO2(g) ↔ SO3(g) + NO(g)      Kc = 0.33

<u>Step 3:</u> Define the direction of the shift of  reaction:

When Q<K, there are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.

When Q>K, there are more products than reactants. To decrease the amount of products, the reaction will shift to the left and produce more reactants.

When Q=K, the system is at equilibrium and there is no shift to either the left or the right.

<u>Step 4:</u> Calculate Q

Q = [NO][SO3]/[SO2][NO2]

Q = (0.14 *0.12)/(0.41*0.14)

Q = 0.0168/0.0574

Q = 0.293

Q<Kc

This means there are more reactants than products. Thud, some of the reactants will become products, causing the reaction to shift to the right.

The reaction will shift in the direction of products.

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fredd [130]

Answer: The final pressure is 0.81 kPa

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.58 kPa

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = v

V_2 = final volume of gas = v-\frac{40}{100}\times v=0.6v

T_1 = initial temperature of gas = 25^0C=(25+273)K=298K

T_2 = final temperature of gas = -22^0C=(-22+273)K=251K

Now put all the given values in the above equation, we get:

\frac{0.58\times v}{298}=\frac{P_2\times 0.6v}{251}

P_2=0.81kPa

The final pressure is 0.81 kPa

3 0
2 years ago
A compressed gas cylinder is filled with 5270 g of argon gas. The pressure inside the cylinder is 2050 psi at a temperature of 1
LuckyWell [14K]

Answer:

A compressed gas cylinder is filled with 5270 g of argon gas.

The pressure inside the cylinder is 2050 psi at a temperature of 18C.

The valve to the cylinder is opened and gas escapes until the pressure inside the cylinder is 650. psi and the temperature are 26 C.

How many grams of argon remains in the cylinder?

Explanation:

First, calculate the volume of argon gas that is present in the gas cylinder by using the ideal gas equation:

Mass of Ar gas is --- 5270g.

The number of moles of Ar gas:

Number of moles of Ar gas=\frac{given mass of Ar}{its atomic mass} \\                                             =\frac{5270g}{39.948g/mol} \\                                             =131.9mol

Temperature T=(18+273)K=291K

Pressure P=2050psi

2050* 0.0680atm\\\\=139.4atm\\

Volume V=?

PV=nRT\\139.4atm * V=131.9mol *0.0821L.atm.mol-1.K-1 * 291K\\=>V=\frac{131.9mol *0.0821L.atm.mol-1.K-1 * 291K}{139.4atm} \\=>V=22.6L

Using this volume V=22.6L

Pressure=650psi=44.2atm

Temperature T= (26+273)K=299K

calculate number of moles "n" value:

PV=nRT\\=>n=\frac{PV}{RT} \\=>n=\frac{44.2atm*22.6L}{0.0821L.atm.mol^-1K^-1* 299K} \\=>n=40.7mol

Mass of 40.7mol of Ar gas:

mass of Ar gas=number of moles * its atomic mass\\\\                        =40.7mol* 39.948g/mol\\\\                        =1625.8g

Answer:

The mass of Ar gas becomes 1625.8g.

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What do people mean when they say everything is connected
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A network.. where one thing ends another begins
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Describe the double circulation system of the human body
Alika [10]

Answer:

we have two loops in our body in which blood circulates. One is oxygenated, meaning oxygen rich, and the other is deoxygenated, which means it has little to no oxygen, but a lot of carbon dioxide.

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Which best describes a stock solution that is used in a dilution?
RSB [31]
A stock solution is a solution of a known concentration. Stock solution has a high concentration and therefore, the known amount of stock solution is used for preparing different concentrations, by diluting the same with the known amount of the solvent being used, such as water. 
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