Electrons(shiwhgsvdjdjwvndkshwgvsbdjdhhagdbdjjshwvwb)
The correct answer is answer choice B, 2. Calcium is in Column 2, meaning that it has 2 electrons in its outermost energy level. These two electrons must be lost for it to form an ionic bond with another element and become stable.
Questions like these can be easily answered if you have a periodic table on hand. Elements in Column 1 need to lose 1 electron to form ionic bonds, elements in Column 2 need to lose 2, and so on. Keep in mind, however, that elements in the center of the table are more likely to form metallic or covalent bonds, and elements in Columns 16 and 17 need to gain 2 and 1 electrons, respectively.
Answer:
1) Without our atmosphere we wouldn't have life! The atmosphere protects our earth from letting harmful substances or rocks into our planet, which could cause damage.
2) You interact with the atmosphere in both good ways and bad. You interact by putting up things like flowers and trees, but in bad ways by releasing bad things (like carbon dioxide) and by light pollution!
3) The factors that can affect climate of an area, by latitude and longitude!
Explanation:
Hope this helps! Plz mark as brainliest! :)
Answer:
C₂H₅O₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 0.25 g
Mass of CO₂ = 0.3664 g
Mass of H₂O = 0.15 g
Empirical formula =?
Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:
For Carbon (C):
Mass of CO₂ = 0.3664 g
Molar mass of CO₂ = 12 + (2×16) = 44 g/mol
Mass of C = 12/44 × 0.3664
Mass of C = 0.1
For Hydrogen (H):
Mass of H₂O = 0.15 g
Molar mass of H₂O = (2×1) + 16 = 18 g/mol
Mass of H = 2/18 × 0.15
Mass of H = 0.02 g
For Oxygen (O):
Mass of C = 0.1 g
Mass of H = 0.02 g
Mass of compound = 0.25 g
Mass of O =?
Mass of O = (Mass of compound) – (Mass of C + Mass of H)
Mass of O = 0.25 – (0.1 + 0.02)
Mass of O = 0.25 –0.12
Mass of O = 0.13 g
Finally, we shall determine the empirical formula for the compound. This can be obtained as follow:
C = 0.1
H = 0.02
O = 0.13
Divide by their molar mass
C = 0.1 / 12 = 0.0083
H = 0.02 / 1 = 0.02
O = 0.13 / 16 = 0.0081
Divide by the smallest
C = 0.0083 / 0.0081 = 1
H = 0.02 / 0.0081 = 2.47
O = 0.008 / 0.008 = 1
Multiply by 2 to express in whole number
C = 1 × 2 = 2
H = 2.47 × 2 = 5
O = 1 × 2 = 2
Thus, the empirical formula for the compound is C₂H₅O₂
Given data:
Hydrogen (H) = 3.730 % by mass
Carbon (C) = 44.44%
Nitrogen (N) = 51.83 %
This means that if the sample weighs 100 g then:
Mass of H = 3.730 g
Mass of C = 44.44 g
Mass of N = 51.83 g
Now, calculate the # moles of each element:
# moles of H = 3.730 g/ 1 g.mole-1 = 3.730 moles
# moles of C = 44.44/12 = 3.703 moles
# moles of N = 51.83/14 = 3.702 moles
Divide by the lowest # moles:
H = 3.730/3.702 = 1
C = 3.703/3.702 = 1
N = 3.702/3.702 = 1
Empirical Formula = HCN
