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3 years ago

The splitting apart of an ester in the presence of a strong acid and water is called

Chemistry

1 answer:

Alenkasestr [34]3 years ago

5 0

The splitting apart of an ester in the presence of a strong acid and water is called hydrolysis.

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How many moles of Al are needed to react completely with 1.2 moles of Fe0

DIA [1.3K]

0.8 moles

3 moles of feO gives you 2 moles of Al and 1.2 of your moles should give you 1.2 divided by 3*2 so it equals 0.80 moles

Right?

7 0

2 years ago

How much energy is released when 22.4g of CH4 is burned?

solniwko [45]

The combustion of methane, CH4, releases 890.4 kJ/mol. That is, when one mole of methane is burned, 890.4 kJ are given off to the surroundings. This means that the products have 890.4 kJ less than the reactants.

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2 years ago

The controlled Release of nuclear energy in a creator is accomplished by: allowing the critical mass of fuel to react . Controll

pishuonlain [190]

Answer:

If a chain reaction takes place, the amount of energy released would increase exponentially, so in order to control the energy release, fission must be controlled without controlling a chain reaction, so the third option is correct.

Hope this helps!

Explanation:

4 0

3 years ago

The movement of one or more from one reactant to another is called

mrs_skeptik [129]

Answer: Redox Reaction

Explanation:

Redox reaction is the key chemical events in an oxidation-reduction also called Redox. It is the net movement of electrons from one reactants to another

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3 years ago

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O)? For example if th

oee [108]

Given :

Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .

To Find :

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .

Solution :

By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.

So , volume of solution does not matter .

Moles of oxygen , $n=\dfrac{2.666}{16}=0.167\ mole$ .

Now , molecule of CO contains 1 mole of C .

So , moles of C is also 0.167 mole .

Mass of carbon , $m=12\times 0.167=2\ g$ .

Therefore , mass of carbon is 2 grams .

Hence , this is the required solution .

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2 years ago