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VikaD [51]
3 years ago
11

What is the mole fraction of water in 200g of 95% (by mass) ethanol, C2H5OH? C2H5OH= 46g/mol

Chemistry
1 answer:
zheka24 [161]3 years ago
5 0
For the given 200 g of 95% ethanol solution, ethanol is 190g and water is 10g. We determine the number of moles per component.
        ethanol:    (190 g ethanol) / (46 g/mole) = 4.13 moles
         water:      (10 g water)/(18 g/mole) = 0.55 moles

Total moles of the solution is 4.68 moles

Mole fraction of water:  = 0.55 moles/4.68 moles = 0.117
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Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL
dybincka [34]

Answer:

M_2=3.34x10^{-3}M

Explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

M_1V_1=M_2V_2

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

M_2=\frac{M_2V_2}{V_1} =\frac{45.45mL*0.0404M}{550.00mL}\\\\M_2=3.34x10^{-3}M

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5 0
2 years ago
A geometric isomer with two alkyl groups on the same side of the carbon-carbon double bond is called
grandymaker [24]
Answer:
             <span>A geometric isomer with two alkyl groups on the same side of the carbon-carbon double bond is called <em>cis</em> Isomer.

Explanation:
                   Geometric isomerism takes place about the double bond in alkenes when the alkyl groups are either situated at the same side (<em>cis</em>) or are situated opposite (<em>trans</em>) to each other.

Example:
               <em>cis</em>-2-Butene (highlighted red)

               <em>trans</em>-2-Butene (highlighted blue)</span>

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3 years ago
The following thermochemical equation is for the reaction of nitrogen(g) with oxygen(g) to form nitrogen dioxide(g). N2(g) + 2O2
Rzqust [24]

<u>Answer:</u> The mass of nitrogen gas reacted to produce given amount of energy is 5.99 grams.

<u>Explanation:</u>

The given chemical reaction follows:

N_2(g)+2O_2(g)\rightarrow 2NO_2(g);\Delta H=66.4kJ

We know that:

Molar mass of nitrogen gas = 28 g/mol

We are given:

Enthalpy change of the reaction = 14.2 kJ

To calculate the mass of nitrogen gas reacted, we use unitary method:

When enthalpy change of the reaction is 66.4 kJ, the mass of nitrogen gas reacted is 28 grams.

So, when enthalpy change of the reaction is 14.2 kJ, the mass of nitrogen gas reacted will be = \frac{28}{66.4}\times 14.2=5.99g

Hence, the mass of nitrogen gas reacted to produce given amount of energy is 5.99 grams.

8 0
3 years ago
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user100 [1]

Answer:

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Because it has two syllables
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