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VikaD [51]
3 years ago
11

What is the mole fraction of water in 200g of 95% (by mass) ethanol, C2H5OH? C2H5OH= 46g/mol

Chemistry
1 answer:
zheka24 [161]3 years ago
5 0
For the given 200 g of 95% ethanol solution, ethanol is 190g and water is 10g. We determine the number of moles per component.
        ethanol:    (190 g ethanol) / (46 g/mole) = 4.13 moles
         water:      (10 g water)/(18 g/mole) = 0.55 moles

Total moles of the solution is 4.68 moles

Mole fraction of water:  = 0.55 moles/4.68 moles = 0.117
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Which compound reacts with an acid to produce water and a salt
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3 years ago
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A longer growing season is a result of
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4 years ago
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Two different compounds are formed by the elements nitrogen and oxygen. The first compound, compound P1, contains 64.17% by mass
xz_007 [3.2K]

Answer:

Explanation:

To solve the problem, we must know the kind of compounds we are dealing with.

For the first compound, P1 and second compound P2:

                                N                       O                         N                     O

Mass percent       64.17                 35.73                  47.23               52.79

Atomic mass          14                      16                         14                    16

Number of

moles            64.17/14            35.73/16            47.23/14    52.79/16      

                            4.58                  2.23                     3.37                  3.30

Simplest

ratio                 4.58/2.23            2.23/2.23             3.37/3.30         3.3/3.3

                              2                           1                             1                        1

                             

P1 compound is N₂O

P2 compound is NO

These are the compounds,

   In N₂O = 28:16

          NO = 14:16

This is the ratio of nitrogen to a fixed mass of oxygen for the two compounds.

7 0
3 years ago
A gas occupies 547 L at 331K. Find its volume at 376K. You must show all of your work to receive credit. Also, name the gas law
zysi [14]

621.4L

Explanation:

Given parameters:

Initial volume = 547L

Initial temperature = 331K

Final temperature = 376K

Unknown:

Final volume = ?

Solution:

The appropriate gas law to use is the Charles's law.

The Charles's law shows the relationship between the volume and temperature of a gas under constant pressure.

The law states that "The volume of a fixed of a gas varies directly as its absolute temperature if the pressure is constant".

Mathematically;

    \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

 V₁ is the initial volume

 T₁ is the initial temperature

 V₂ is the final volume

 T₂ is the final temperature

Since the unknown is the final volume, we make it the subject of the expression;

   V₂ = \frac{V_{1} }{T_{1} }  x T_{2}  = \frac{547}{331 }  x 376

 V₂ =  621.4L

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

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