Depending on what you are working with, it would be a solid
Answer: -7J
Explanation:
To determine the change in potential energy, use the equation ΔPE=mgΔh
Δ
PE=mg
Δ
h
, where m is the mass, g= 9.8 m/s2
g= 9.8 m/s
2
, and Δh is the change in height. Hence, we have that the potential energy PE=4.0 kg×9.8 m/s2×-2.0 m=-78 J
PE=4.0 kg
×
9.8 m/s
2
×
-2.0 m=-78 J
. To verify that this is correct, note that since the cat changes the potential energy to kinetic energy by jumping, the potential energy decreases. Hence, the potential energy should be negative.
Answer:
My answer is=
Ocean surface:0
Seaweed:(-20)
Clownfish:(-23)
Squid:(-44)
Ocean floor:(-50)
(I'm very sorry if I was wrong T~T)
Mass, m = 4g = 0.004 kg
Velocity, = 50cm/s = 0.5m/s
Distance, 10cm = 0.1m
The wall would have to resist the energy acquired by the bullet.
Kenetic Energy of bullet = Resistance offered by the wall.
1/2 mv² = Resistance Force * Distance
(1/2) * 0.04 * 0.5 * 0.5 = F * 0.1
0.5 * 0.04 * 0.5 * 0.5 = F * 0.1
0.5 * 0.04 * 0.5 * 0.5/0.1 = F
0.05 = F
Therefore, Resistance offered by the wall = 0.05 N
The radius of the circle, in cm, after t seconds would be 50t
The area, A, of the circle after t seconds is expressed in the equation: A = pi * r^2
A = pi * (50T)^2 = pi*2500*t^2
The change of area per unit time is obtained by differentiating the equation
A' = pi*2500*2*t A' = pi*5000*t
when t = 3 secondsA' = pi*5000*3 = 47122 cm2/s
