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topjm [15]
3 years ago
9

What is the predominant intermolecular force in the liquid state of each of these compounds: water (H2O), carbon tetrabromide (C

Br4), and dichloromethane (CH2Cl2)? Drag the appropriate items to their respective bins. View Available Hint(s) ResetHelp Dipole-dipole forces Hydrogen bonding Dispersion forces
Chemistry
1 answer:
Valentin [98]3 years ago
8 0

Explanation:

  • Water -

It shows , Hydrogen bonding , Since ,

The molecule of water have a strong electronegative atom of oxygen and a hydrogen atom ,

So , the electronegative oxygen atom can interact with the other hydrogen atom of the other water molecule .

  • Carbon tetrabromide -

The molecule of Carbon tetrabromide have polar bonds of carbon and bromine atom , but overall the molecule is non - polar in nature , due to its tetraderal structure , hence ,

the molecule shows only dispersion forces .

  • dichloromethane -

The molecule of dichloromethane has Dipole Dipole forces due to difference in electronegativity between atoms .

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Land Breeze is the answer

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Calculate molality,molarity and mole fraction of KI if the density of 20%(mass) aqueous KI is 1.202 g/mL
Scorpion4ik [409]
Basis: 1 L of the substance.
               (1.202 g/mL) x (1000 mL) = 1202 g 
                   mass solute = (1202 g) x 0.2 = 240.2 g
                   mass solvent = 1202 g x 0.8 =  961.6 g
                   moles KI = (240.2 g) x (1 mole / 166 g)  = 1.45 moles
                   moles water = (961.6 g) x (1 mole / 18 g) = 53.42 moles
1. Molality = moles solute / kg solvent 
                  = 1.45 moles / 0.9616 kg = 1.5 m
2. Molarity = moles solute / L solution
                  = 1.45 moles / 1 L solution = 1.45 M
3. molar mass = mole solute / total moles
                        =  1.45 moles / (1.45 moles + 53.42 moles) = 0.0264 

5 0
3 years ago
Which statement describes clean air as a natural resource? Select three options.
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a,d,e

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2 years ago
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er solutions can be produced by mixing a weak acid with its conjugate base or by mixing a weak base with its conjugate acid. The
liubo4ka [24]

Answer:

You need to add 19,5 mmol of acetates

Explanation:

Using the Henderson-Hasselbalch equation:

pH = pKa + log₁₀ [base]/[acid]

For the buffer of acetates:

pH = pKa + log₁₀ [CH₃COO⁻]/[CH₃COOH]

As pH you want is 5,03, pka is 4,74 and milimoles of acetic acid are 10:

5,03 = 4,74 + log₁₀ [CH₃COO⁻]/[10]

1,95 = [CH₃COO⁻]/[10]

<em>[CH₃COO⁻] = 19,5 milimoles</em>

Thus, to produce an acetate buffer of 5,03 having 10 mmol of acetic acid, you need to add 19,5 mmol of acetates.

I hope it helps!

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