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topjm [15]
4 years ago
9

What is the predominant intermolecular force in the liquid state of each of these compounds: water (H2O), carbon tetrabromide (C

Br4), and dichloromethane (CH2Cl2)? Drag the appropriate items to their respective bins. View Available Hint(s) ResetHelp Dipole-dipole forces Hydrogen bonding Dispersion forces
Chemistry
1 answer:
Valentin [98]4 years ago
8 0

Explanation:

  • Water -

It shows , Hydrogen bonding , Since ,

The molecule of water have a strong electronegative atom of oxygen and a hydrogen atom ,

So , the electronegative oxygen atom can interact with the other hydrogen atom of the other water molecule .

  • Carbon tetrabromide -

The molecule of Carbon tetrabromide have polar bonds of carbon and bromine atom , but overall the molecule is non - polar in nature , due to its tetraderal structure , hence ,

the molecule shows only dispersion forces .

  • dichloromethane -

The molecule of dichloromethane has Dipole Dipole forces due to difference in electronegativity between atoms .

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Convert 256.3 g sodium carbonate to formula units
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The d orbital in the most stable configuration for Cu would be one that has how many electrons
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A mixture 21.2 g of P and 79.0 g Cl2 reacts completely to form PCl3 and PCl5 as the only products. find the mass of PCl3
IRISSAK [1]

Considering the definition of reaction stoichiometry and limiting reagent, the mass of PCl₃ that could be formed is 38.26 grams.

In first place, you must know that the balanced reaction is:

4 Cl₂ + 2 P → PCl₃ + PCl₅

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • Cl₂: 4 moles
  • P: 2 moles
  • PCl₃: 1 mole
  • PCl₅: 1 mole

The molar mass of the compounds is:

  • Cl₂: 70.9 g/mole
  • P: 31 g/mole
  • PCl₃: 137.35 g/mole
  • PCl₅: 208.25 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • Cl₂: 4 moles× 70.9 g/mole = 283.6 grams
  • P: 2 moles× 31 g/mole= 62 grams
  • PCl₃: 1 mole× 137.35 g/mole= 137.35 grams
  • PCl₅: 1mole× 208.25 g/mole= 208.25 grams

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 62 grams of P reacts with 283.6 grams of Cl₂, 21.2 grams of P reacts with how much mass of Cl₂?

mass of Cl_{2}=\frac{21.2 grams of Px283.6 grams of Cl_{2} }{62 grams of P}

<u><em>mass of Cl₂= 96.97 grams </em></u>

But 96.97 grams of Cl₂ are not available, 79 grams are available. Since you have less mass than you need to react with 21.2 grams of P, Cl₂ will be the limiting reagent.

Then, it is possible to determine the mass of PCl₃ produced by another rule of three, using the limiting reagent: if by stoichiometry 283.6 grams of Cl₂ produce 137.35 grams of PCl₃, 79 grams of Cl₂ how much mass of PCl₃ will be formed?

mass of PCl_{3}=\frac{137.35 grams of PCl_{3}x79 grams of Cl_{2} }{283.6grams of Cl_{2}}

<u><em>mass of PCl₃= 38.26 grams</em></u>

In summary, the mass of PCl₃ that could be formed is 38.26 grams.

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