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MArishka [77]
3 years ago
10

How many moles of argon atoms are present in 100 l of argon gas at stp?

Chemistry
2 answers:
eimsori [14]3 years ago
6 0
<em>We know<u> One mole of Argon occupy the volume of 22.4 L
</u>
</em>
<em>Therefore , 22.4 L of Argon weighs 40 g.</em>
<em>∴ 1 L of Argon weighs ,  40/22.4 </em>
<em>∴ 100 L of Argon weighs (40/22.4 ) × 100</em>
<em>= 178.57 g.</em>


<em>Hence <u>moles of Argon is 178.57 g.


</u>Hope it Helps :-)
</em>
saveliy_v [14]3 years ago
5 0
One mole of Argon occupy the volume of 22.4 L
Therefore , 22.4 L of Argon weighs 40 g.∴ 1 L of Argon weighs ,  40/22.4 ∴ 100 L of Argon weighs (40/22.4 ) × 100= 178.57 g.

Hence moles of Argon is 178.57 g.


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Empirical formula:

It is the simplest formula gives the ratio of atoms of different elements in small whole number

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            C                      :        H            :         O

           1.7/1.7                :     3.3/1.7       :       1.7/1.7

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C : H : O = 1 : 2 : 1

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Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

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