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Yuri [45]
3 years ago
11

What are some of the best study methods when you have a day to study.

Chemistry
2 answers:
Marta_Voda [28]3 years ago
7 0
For English like vocab I write all the words on flashcard ( one time studying
then I go over them(second time)
I test myself ,what ever words i don't know,I'll put in a seperate pile.
then go through that pile and keep doing that process for history I make power points your reading and writing the information over again exposing yourself twice or you can YouTube videos on the subject
madam [21]3 years ago
4 0
For me, it depends on the subject. Because I'm weird.
For social studies related classes, usually just reviewing facts is enough to let me get good test/quiz scores.
For science classes, I review the topics that I had the most trouble with, because science comes naturally to me, so the rest is easy.
For math, since I struggle with that the most, I put the most study time into it. I take whatever topics from the class that confused me most, and just do random problems related to that topic. This actually helps a great deal.
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In the following reaction HF(aq) + HPO42-(aq) = F-(aq) + H2PO4-(aq)
garik1379 [7]

Answer:

d

Explanation:

HF gives its H to HPO42 making it H2PO4, so HF is the acid and F- is the conj base

6 0
3 years ago
The 10x SDS gel electrophoresis buffer contains 250mM Tris HCl, 1.92M Glycine, and 1% (w/v) SDS. Buffers are always used at 1x c
olchik [2.2K]

Answer:

25 mM Tris HCl and 0.1% w/v SDS

Explanation:

A <em>10X solution</em> is ten times more concentrated than a <em>1X solution</em>. The stock solution is generally more concentrated (10X) and for its use, a dilution is required. Thus, to prepare a buffer 1X from a 10X buffer, you have to perform a dilution in a factor of 10 (1 volume of 10X solution is taken and mixed with 9 volumes of water). In consequence, all the concentrations of the components are diluted 10 times. To calculate the final concentration of each component in the 1X solution, we simply divide the concentration into 10:

(250 mM Tris HCl)/10 = 25 mM Tris HCl

(1.92 M glycine)/10 = 0.192 M glycine

(1% w/v SDS)/10 = 0.1% w/v SDS

Therefore the final concentrations of Tris and SDS are 25 mM and 0.1% w/v, respectively.

7 0
3 years ago
Alcohol is removed by the _________ blank at a constant rate of 0.25 to 0.30 ounce of ethanol per hour
nekit [7.7K]

Answer:

Liver

Explanation:

Some of these intermediate metabolites can have harmful effects on the body. Most of the ethanol in the body is broken down in the liver by an enzyme called alcohol dehydrogenase (ADH), which transforms ethanol into a toxic compound called acetaldehyde (CH3CHO), a known carcinogen.

7 0
3 years ago
HELP!!
NARA [144]
A dichotomous key is an important scientific tool, used to identify different organisms, based the organism's observable traits. Dichotomous keys consist of a series of statements with two choices in each step that will lead users to the correct identification.
8 0
3 years ago
Which of the following reactions is not an example of a neutralization reaction?
Dafna1 [17]

Answer:

The answers are B and D.

Explanation:

This is because neutralisation process that contain sodium, potassium and ammonium will produce salt and water.

3 0
3 years ago
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