Answer:
0.00714 g
Explanation:
We know that the volume of one mole of a substance is 22400 cm^3
Thus;
1 mole of sulphur occupies 22400 cm^3
x moles of sulphur occupies 5.0 cm3
x = 5.0 cm3 * 1 mole/22400 cm^3
x = 2.23 * 10^-4 moles
Molar mass of sulphur = 32 g/mol
Mass of sulphur = 2.23 * 10^-4 moles * 32 g/mol
Mass of sulphur = 0.00714 g
In this problem, you’re given a mass (m) and a force (F) applied to an object and you’re asked to calculate the acceleration (a). If we plug this into the provided equation:
F = ma
(7.3 N) = (3.2 kg)a
a = 2.3 m/s/s
The acceleration of the object is 2.3 m/s/s.
Hope this helps!
Answer:
K = 137.55 atm/M.
Explanation:
- The relationship between gas pressure and the concentration of dissolved gas is given by Henry’s law:
<em>P = (K)(C)</em>
where P is the partial pressure of the gaseous solute above the solution (P = 1.0 atm).
k is a constant (Henry’s constant).
C is the concentration of the dissolved gas (C = 7.27 x 10⁻³ M).
∴ K = P/C = (1.0 atm)/(7.27 x 10⁻³ M) = 137.55 atm/M.
Answer:
wind
pollution free no use of resources