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vovikov84 [41]
3 years ago
13

The root-mean-square value of an alternating current of S0Hz frequency is 10 ampere. The time taken by the alternating current i

n reaching from zero to maximum value and the peak value of current will be (A) 2x10-2 sec and 14.14 amp. (C) 5 x 10-3 sec and 7.07 amp. (B) 1 x 102 sec and 7.07 amp. (D) 5x10 scc and 14.14 amp.

Physics
1 answer:
stealth61 [152]3 years ago
7 0

Answer:

(D ) 5\times10^{-3} sec and 14.14 amp.

Explanation:

Given that, the rms value of current is 10 ampere and its frequency is 50 Hz.

Now maximum value of current can be calculated as,

I_{max}=\sqrt{2}I_{rms}\\I_{max}=10\times \sqrt{2}  \\I_{max}=14.14 amp.

The time period is defined as,

T=\frac{1}{f}\\ T=\frac{1}{50}\\ T=0.02 sec

Now the time taken by alternating current going from zero to maximum value is,

t=\frac{T}{4}\\ t=\frac{0.02}{4}\\ t=5\times 10^{-3}sec

Therefore, the time taken by alternating current to reach maximum value is t=5\times 10^{-3}sec and the peak value of current is 14.14 amp..

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