Question

The root-mean-square value of an alternating current of S0Hz frequency is 10 ampere. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be (A) 2x10-2 sec and 14.14 amp. (C) 5 x 10-3 sec and 7.07 amp. (B) 1 x 102 sec and 7.07 amp. (D) 5x10 scc and 14.14 amp.

Answer 1

Answer:

(D ) $5\times10^{-3} sec$ and $14.14 amp.$

Explanation:

Given that, the rms value of current is 10 ampere and its frequency is 50 Hz.

Now maximum value of current can be calculated as,

$I_{max}=\sqrt{2}I_{rms}\\I_{max}=10\times \sqrt{2} \\I_{max}=14.14 amp.$

The time period is defined as,

$T=\frac{1}{f}\\ T=\frac{1}{50}\\ T=0.02 sec$

Now the time taken by alternating current going from zero to maximum value is,

$t=\frac{T}{4}\\ t=\frac{0.02}{4}\\ t=5\times 10^{-3}sec$

Therefore, the time taken by alternating current to reach maximum value is $t=5\times 10^{-3}sec$ and the peak value of current is $14.14 amp.$.