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Soloha48 [4]
3 years ago
15

Find the distance between the points given. (-3, 2) and (9, -3) 13

Physics
1 answer:
ohaa [14]3 years ago
5 0

The distance between two points on a graph is

Square root of [ (difference in the y-values)² + (difference in the x-values)² ] .

So for these two points, the distance between them is

square root of [ (-5)² + (12)² ] =

square root of [ 25 + 144 ]  =

square root of [ 169 ] =

<em>13 .</em>

Yes, the ' 13 ' you typed at the end of the question is the correct answer to it.

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The maximum tension that a 0.80 m string can tolerate is 15 N. A 0.35-kg ball attached to this string is being whirled in a vert
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Answer:

v=5.86 m/s

Explanation:

Given that,

Length of the string, l = 0.8 m

Maximum tension tolerated by the string, F = 15 N

Mass of the ball, m = 0.35 kg

We need to find the maximum speed the ball can have at the top of the circle. The ball is moving under the action of the centripetal force. The length of the string will be the radius of the circular path. The centripetal force is given by the relation as follows :

F=\dfrac{mv^2}{r}

v is the maximum speed

v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{15\times 0.8}{0.35}} \\\\v=5.86\ m/s

Hence, the maximum speed of the ball is 5.86 m/s.

3 0
3 years ago
Between 1911 and 1990, the top of the leaning bell tower at Pisa, Italy, moved toward the south at an average rate of 1.2 mm/y.T
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Answer:

Angular speed, \omega=6.90\times 10^{-13}\ rad/s

Explanation:

It is given that,    

The top of the leaning bell tower at Pisa, Italy, moved toward the south at an average rate of, v = 1.2 mm/yr

1\ mm/yr=3.171\times 10^{-11}\ m/s

Velocity, v=3.80\times 10^{-11}\ m/s

Height of the tower, h = 55 m

The height of the tower is equivalent to the radius. Let \omega is the angular speed of the tower’s top about its base. The relation between the angular speed and the angular speed is given by :

v=r\omega

\omega=\dfrac{v}{r}

\omega=\dfrac{3.80\times 10^{-11}\ m/s}{55\ m}

\omega=6.90\times 10^{-13}\ rad/s

So, the average angular speed of the tower’s top about its base is 6.90\times 10^{-13}\ rad/s. Hence, this is the required solution.

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