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nikdorinn [45]
3 years ago
5

A student attempts to slide a block down a smooth, dry ramp as shown, but the block does not move. The most likely explanation i

s that:
a. the ramp is not steep enough for gravity to have any effect.
b. there is no normal force between the block and ramp.
c. the coefficient of dry sliding friction is too small to allow the block to slide.
d. the coefficient of static friction is too large to allow the block to slide.
Physics
1 answer:
Rashid [163]3 years ago
6 0

Answer:

B

Explanation:

The normal force would be that the ramp would be dry

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Similarities and differences between<br> distance Time graph and velocity time<br> graph?
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Similarity: >>Time is independent variable and such is on the x-axis. ... >>Distance time graph tells you how much distance you have travelled, while velocity time graph tells you your acceleration.  The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.

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A combined circuit has two resistors in series (27.5 ohms and 33.0 ohms) and another in parallel (22.0 ohms). If the power sourc
Dafna1 [17]
R 1,2 = 27.5 + 33.0 = 60.5 Ohms
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4 0
3 years ago
An 8.75 kg point mass and a 14.0 kg point mass are held in place 50.0 cm apart. A particle of mass m is released from a point be
marysya [2.9K]

Answer

given,

mass of the = m₁ = 8.75 Kg

another mass of the object = m₂ = 14 Kg

distance between them = 50 cm

R₁ = 17 cm

R₂ = 50 -17 = 33 cm

a) Force applied due to the Mass 8.75  in +ve x- direction

F_1 = \dfrac{GM_1 m}{R_1^2}

F_1 = \dfrac{6.67\times 10^{-11} \times 8.75\ m}{0.17^2}

F_1 = 2.019\times 10^{8}\ m

Force applied due to mass 14 Kg in -ve x-direction

F_2 = \dfrac{GM_2 m}{R_2^2}

F_2 = \dfrac{6.67\times 10^{-11} \times 14\ m}{0.33^2}

F_2 = 0.857\times 10^{8}\ m

net force

F = F₁ + F₂

F = 2.019\times 10^{8}\ m - 0.857\times 10^{8}\ m

F = 1.162\times 10^{8}\ m

Using newton second law

a = \dfrac{F}{m}

a = \dfrac{ 1.162\times 10^{8}\ m}{m}

a =1.162\times 10^{8} \ m/s^2

b) As the acceleration of mass comes out to be  +ve hence, the direction will be toward the mass of 8.75 Kg

6 0
3 years ago
1. A ball is thrown downward with an initial speed of 22 m/s on Earth. a. What is the acceleration of the ball? b. Calculate the
vitfil [10]

Answer:

Explanation:

The acceleration of the ball would be due to the downward force of gravity, 9.8m/s^2. In order to find the displacement given that interval of time, you have to use the corresponding kinematic formula:

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To find the required time given a desired final velocity, we can use:

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38=9.8t

t=3.9s

6 0
2 years ago
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