Answer:
ΔU = 5.21 × 10^(10) J
Explanation:
We are given;
Mass of object; m = 1040 kg
To solve this, we will use the formula for potential energy which is;
U = -GMm/r
But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.
Thus;
ΔU = -GMm((1/r_f) - (1/r_i))
Where;
M is mass of earth = 5.98 × 10^(24) kg
r_f is final radius
r_i is initial radius
G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²
Since, it's moving to altitude four times the Earth's radius, it means that;
r_i = R_e
r_f = R_e + 4R_e = 5R_e
Where R_e is radius of earth = 6371 × 10³ m
Thus;
ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)
× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))
ΔU = 5.21 × 10^(10) J
Answer:
Taking gravity to be 9.8m/s2, The velocity is 24.5m/s2.
Taking gravity to be 10m/s2, The velocity is 25m/s2.
Explanation:
According the first formula of motion under the influence of gravity for upward motion, v=u-gt, where v=final velocity, u=initial velocity, and t= time taken.
Here the time taken for the ball to reach the maximum point is half of 5, which is 2.5 seconds.
And v is 0, since at the maximum point gravity slows down the velocity to 0.
Finding the initial velocity,
v=u-gt
0=u-10(2.5)
u=10(2.5)
u=25m/s
To answer this question is necessary to apply the concepts related to Bernoulli's equation. The Bernoulli-related concept describes the behavior of a liquid moving along a streamline. Pressure can be defined as the proportional ratio between height, density and gravity:

Where,
h = Height
= Density
g = Gravity
Our values are
density of water at normal conditions
h = 7.3m

PART A) Replacing these values to find the total pressure difference we have to



In this way the pressure change would be subject to




PART B) Considering the pressure gauge of the group as the ideal so that at a height H the water cannot flow even if it is open we have to,



Therefore the high which could a faucet be before no water would flow from it is 21.42m
Answer:
The magnitude is:
The direction of E is in the negative x-direction.
Explanation:
The electric field equation is:

Where:
- Q is the charge (we can choose the electron or the proton)
- r is the distance (in our case is at the midpoint 973/2 nm)
- k is the Coulomb constant (
)
Using the electron charge (
)
The magnitude is:
The direction of E is in the negative x-direction.
I hope it helps you!