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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics

2 answers:

Roman55 [17]3 years ago

8 0

The correct answer is 132m.

Nostrana [21]3 years ago

4 0

Don't look now, but the question GIVES you the formula to use, and it GIVES you the numbers to plug into the formula.

The formula to use to find the distance covered by the sound is

<em>Speed = (distance) / (time)</em>

They also give you:

speed = 330 m/s

time = 0.40 second

Stuff the numbers into the formula:

330 m/s = (Distance) / (0.40 second)

Multiply each side by (0.40 second), and you get:

(330 m/s) / (0.4 second) = Distance

<em>825 meters = Distance</em>

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The radius of a sphere is increasing at a rate of 4 mm/s. How fast is the volume increasing when the diameter is 60 mm?

jok3333 [9.3K]

V = [4/3]π r^3 => [dV / dr ] = 4π r^2

[dV/dt] = [dV/dr] * [dr/dt]

[dV/dt] = [4π r^2] * [ dr/ dt]

r = 60 mm, [dr / dt] = 4 mm/s

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3 years ago

If the radius of the sun is 7.001×105 km, what is the average density of the sun in units of grams per cubic centimeter? The vol

xenn [34]

Answer:

Average density of Sun is 1.3927 $\frac{g}{cm}$ .

Given:

Radius of Sun = 7.001 × $10^{5}$ km = 7.001 × $10^{10}$ cm

Mass of Sun = 2 × $10^{30}$ kg = 2 × $10^{33}$ g

To find:

Average density of Sun = ?

Formula used:

Density of Sun = $\frac{Mass of Sun}{Volume of Sun}$

Solution:

Density of Sun is given by,

Density of Sun = $\frac{Mass of Sun}{Volume of Sun}$

Volume of Sun = $\frac{4}{3} \pi r^{3}$

Volume of Sun = $\frac{4}{3} \times 3.14 \times [7.001 \times 10^{10}]^{3}$

Volume of Sun = 1.436 × $10^{33}$ $cm^{3}$

Density of Sun = $\frac{ 2\times 10^{33} }{1.436 \times 10^{33} }$

Density of Sun = 1.3927 $\frac{g}{cm}$

Thus, Average density of Sun is 1.3927 $\frac{g}{cm}$ .

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3 years ago

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chubhunter [2.5K]

Answer: The metal with a volume is zinc.

Explanation: Got it right on Edge2020

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