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ioda
3 years ago
5

One watt is equal to which of these values?

Physics
2 answers:
gregori [183]3 years ago
7 0

Answer:

Correct option: 1 joule/second

Explanation:

The Watt is the unit of measure of power of the International System of Units, it is represented by the letter W in uppercase, it owes its name to the Scottish James Watt.

The watt is a unit of power that equals 1 joule per second (1J / s). Or the work of moving a mass of 1 kilogram, a distance of 1 meter in a second of time. Hence the equivalence since force by distance is work and time divided by power. A horsepower equals 775 W. Expressed in units used in electricity, one watt is the electrical power produced by a potential difference of 1 volt and an electric current of 1 ampere (1 voltampere).

dusya [7]3 years ago
3 0
1 W = 1 J/s 
Watt<span> is the unit of measure for power .
</span><span>
</span>Joule is the unit of measure for the energy and the second is the unit of measure for time.


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Lisa [10]
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What is the net force required to accelerate a 884 kg car at 2 m/sec2?
EastWind [94]

Answer:

1768 N

Explanation:

We can solve the problem by using Newton's second law:

F=ma

where

F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, we have a car of mass

m = 884 kg

And its acceleration is

a=2 m/s^2

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3 0
3 years ago
On earth, you swing a simple pendulum in simple harmonic motion with a period of 1.6 seconds. what is the period of this same pe
polet [3.4K]
The period of a simple pendulum is given by
T= 2 \pi  \sqrt{ \frac{L}{g} }
where
L is the pendulum length
g is the acceleration of gravity

If we move the same pendulum from Earth to the Moon, its length L remains the same, while the acceleration of gravity g changes. So we can write the period of the pendulum on Earth as:
T_e= 2 \pi \sqrt{ \frac{L}{g_e} }
where g_e is the acceleration of gravity on Earth, while the period of the pendulum on the Moon is
T_m= 2 \pi \sqrt{ \frac{L}{g_m} }
where g_m is the acceleration of gravity on the Moon. 

If we do the ratio of the two periods, we get
\frac{T_m}{T_e} =  \sqrt{ \frac{g_e}{g_m} }
but the gravity acceleration on the Moon is 1/6 of the gravity acceleration on Earth, so we can write g_e = 6 g_m and we can rewrite the previous ratio as
\frac{T_m}{T_e} = \sqrt{ \frac{6 g_m}{g_m} }=  \sqrt{6}

so the period of the pendulum on the Moon is
T_m =  \sqrt{6}  T_e =  \sqrt{6} (1.6 s)=3.9 s
8 0
4 years ago
A woman sits on a spinning piano stool with her arms extended. When she folds her arms, which of the following occurs? Question
iogann1982 [59]

Answer:

The correct option is that (She decreases her moment of inertia, thereby increasing her angular speed.)

Explanation:

When an object is in circular motion, the vector that describes it is known as angular momentum. Angular momentum is conserved or constant when an object is spinning in a closed system and no external torques are applied to it. An example of conservation of angular momentum is seen when a woman is sitting on a spinning piano stool with her arms extended. Her angular momentum is conserved because the net torque on her is negligibly small as the friction is exerted very close to the pivot point.

When she folds her arms,her rate of spin increases greatly decreasing her moment of inertia. The work she does to pull in her arms results in an increase in rotational kinetic energy( that is, increase in her angular speed). I hope this helps, thanks!

5 0
3 years ago
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kap26 [50]
I know you are Indian by your question, HC Verma class 9 or 11 !!

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7 0
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