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3 years ago

One watt is equal to which of these values?

Physics

2 answers:

gregori [183]3 years ago

7 0

Answer:

Correct option: 1 joule/second

Explanation:

The Watt is the unit of measure of power of the International System of Units, it is represented by the letter W in uppercase, it owes its name to the Scottish James Watt.

The watt is a unit of power that equals 1 joule per second (1J / s). Or the work of moving a mass of 1 kilogram, a distance of 1 meter in a second of time. Hence the equivalence since force by distance is work and time divided by power. A horsepower equals 775 W. Expressed in units used in electricity, one watt is the electrical power produced by a potential difference of 1 volt and an electric current of 1 ampere (1 voltampere).

dusya [7]3 years ago

3 0

1 W = 1 J/s
Watt is the unit of measure for power .

Joule is the unit of measure for the energy and the second is the unit of measure for time.

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Find the mass of a sample of water if its temperature dropped 24.8 °C when it lost 870 J of

rosijanka [135]

Answer:

8.35 × $10^{-3}$ kg

Explanation:

Remember the formula for heat:

$Q=mc\Delta T$

You just need to solve for m, doing so you're left with:

$m=\dfrac{Q}{c\Delta T}$

Replace the variables with numbers and that's it.

7 0

2 years ago

I wish to use a step up transformer to turn an initial RMS AC voltage of 100 V into a final RMS AC voltage of 200 V. What is the

zhuklara [117]

Answer:

1:2

Explanation:

It is given that,

Initial RMS AC voltage is 100 V and final RMS AC voltage is 200 V.

We need to find the ratio of the number of turns in the primary to the secondary for step up transformer.

For a transformer, $\dfrac{V_1}{V_2}=\dfrac{N_1}{N_2}$

So,

$\dfrac{N_1}{N_2}=\dfrac{100}{200}\\\\\dfrac{N_1}{N_2}=\dfrac{1}{2}$

So, the ratio of the number of turns in the primary to the secondary is 1:2.

4 0

3 years ago

I SERIOUSLY can't do this type of questions so can someone solve it detailedly and putting with letters (there is a system you n

KatRina [158]

Answer:

4 Ohms

Explanation

(This is seriously not as hard as it looks :)

You only need two types of calculations:

replace two resistances, say, R1 and R2, connected in a series by a single one R. In this case the new R is a sum of the two: $R = R_1+R_2$
replace two resistances that are connected in parallel. In that case: $\frac{1}{R}= \frac{1}{R_1}+\frac{1}{R_2}\\\mbox{or}\\R= \frac{R_1\cdot R_2}{R_1+R_2}$

I am attaching a drawing showing the process of stepwise replacement of two resistances at a time (am using rectangles to represent a resistance). The left-most image shows the starting point, just a little bit "warped" to see it better. The two resistances (6 Ohm next to each other) are in parallel and are replaced by a single resistance (3 Ohm, see formula above) in the top middle image. Next, the two resistances (9 and 3 Ohm) are nicely in series, so they can be replaced by their sum, which is what happened going to the top right image. Finally we have two resistances in parallel and they can be replaced by a single, final, resistance as shown in the bottom right image. That (4 Ohms) is the equivalent resistance of the original circuit.

Using these two transformations you will be able to solve step by step any problem like this, no matter how complex.