All categories

3 years ago

One watt is equal to which of these values?

Physics

2 answers:

gregori [183]3 years ago

7 0

Answer:

Correct option: 1 joule/second

Explanation:

The Watt is the unit of measure of power of the International System of Units, it is represented by the letter W in uppercase, it owes its name to the Scottish James Watt.

The watt is a unit of power that equals 1 joule per second (1J / s). Or the work of moving a mass of 1 kilogram, a distance of 1 meter in a second of time. Hence the equivalence since force by distance is work and time divided by power. A horsepower equals 775 W. Expressed in units used in electricity, one watt is the electrical power produced by a potential difference of 1 volt and an electric current of 1 ampere (1 voltampere).

dusya [7]3 years ago

3 0

1 W = 1 J/s
Watt is the unit of measure for power .

Joule is the unit of measure for the energy and the second is the unit of measure for time.

You might be interested in

Who could explain the phenomenom of interference of light?

Likurg_2 [28]

Answer:

When the waves reflected from the inner and outer surface combine they will interfere with each other, removing or reinforcing some parts of white light by destructive or constructive interference. ... This results in color.

Explanation:

this is what we studied

so basically there is like a surface

and 2 different waves coming out of the same source

they will combine and start removing parts of the white light (which originally consists of 6 to 7 colors)

results in showing these colors

6 0

3 years ago

Many physical quantities are connected by inverse square laws, that is, by power functions of the form f(x)=kx^(-2). In particul

goldenfox [79]

Answer:

4 times

Explanation:

Since the equation for the illumination of an object, i.e. the brightness of the light, is inversely proportional to the square of the distance from the light source, the form of the function is:

f(x) = k.x⁻²

Where x is the distance between the object and the light force, k is the constant of proportionality, and f(x) is the brightness.

Then, if you move halfway to the lamp the new distance is x/2 and the new brightness (call if F) is :

$F=k(x/2)^{-2}=\frac{k}{(x/2)^2}= \frac{k}{x^2}. 4=f(x).4$

Then, you have found that the light is 4 times as bright as it originally was.

3 0

3 years ago

What is the length of an aluminum rod at 65Â°C if its length at 15Â°C is 1.2 meters? A. 0.00180 meter B. 1.201386 meters C. 1.2

Deffense [45]

Answer:

Option B is the correct answer.

Explanation:

Thermal expansion

$\Delta L=L\alpha \Delta T$

L = 1.2 meter

ΔT = 65 - 15 = 50°C

Thermal Expansion Coefficient for aluminum, α = 24 x 10⁻⁶/°C

We have change in length

$\Delta L=L\alpha \Delta T=1.2\times 24\times 10^{-6}\times 50=1.44\times 10^{-3}m$

New length = 1.2 + 1.44 x 10⁻³ = 1.2014 m

Option B is the correct answer.

3 0

3 years ago

Read 2 more answers

An offshore oil well is 2 kilometers off the coast. The refinery is 4 kilometers down the coast. Laying pipe in the ocean is twi

shusha [124]

Answer:

Rectangular path

Solution:

As per the question:

Length, a = 4 km

Height, h = 2 km

In order to minimize the cost let us denote the side of the square bottom be 'a'

Thus the area of the bottom of the square, A = $a^{2}$

Let the height of the bin be 'h'

Therefore the total area, $A_{t} = 4ah$

The cost is:

C = 2sh

Volume of the box, V = $a^{2}h = 4^{2}\times 2 = 128$ (1)

Total cost, $C_{t} = 2a^{2} + 2ah$ (2)

From eqn (1):

$h = \frac{128}{a^{2}}$

Using the above value in eqn (1):

$C(a) = 2a^{2} + 2a\frac{128}{a^{2}} = 2a^{2} + \frac{256}{a}$

$C(a) = 2a^{2} + \frac{256}{a}$

Differentiating the above eqn w.r.t 'a':

$C'(a) = 4a - \frac{256}{a^{2}} = \frac{4a^{3} - 256}{a^{2}}$

For the required solution equating the above eqn to zero:

$\frac{4a^{3} - 256}{a^{2}} = 0$

a = 4

Also

$h = \frac{128}{4^{2}} = 8$

The path in order to minimize the cost must be a rectangle.

8 0

3 years ago

A 2000 kg roller coaster is at the top of a loop with a radius of 24 m. If its speed is 18 m/s at this point, what force does it

levacccp [35]

Answer:

$46620\ \text{N}$

Explanation:

m = Mass of roller coaster = 2000 kg

r = Radius of loop = 24 m

v = Velocity of roller coaster = 18 m/s

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Normal force at the point will be

$N-mg=\dfrac{mv^2}{r}\\\Rightarrow N=\dfrac{mv^2}{r}+mg\\\Rightarrow N=\dfrac{2000\times 18^2}{24}+2000\times 9.81\\\Rightarrow N=46620\ \text{N}$

The force exerted on the track is $46620\ \text{N}$ .

8 0

3 years ago