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antoniya [11.8K]
3 years ago
14

Jake pulls a couch of mass 23 kg across his apartment. He pulls on the couch at an angle of 32 degrees. with a force of 120 N. T

he free-body diagram is shown below.
a. What is the x-component of his applied force?


b. What is the y-component of his applied force?


c. Assuming the couch does not leave the ground, what is the normal force acting on the couch?

Physics
2 answers:
Leviafan [203]3 years ago
4 0

a) Simply calculate projection: F.Jake.x=120 cos(32)=101.77 N

b) Likewise: F.Jake.y=120 sin(32)=63.59 N

c) F.N - W + F.Jake.y = 0, so

F.N = W - F.Jake.y = mg - F.Jake.y = 161.81 N

ludmilkaskok [199]3 years ago
4 0

Answer:

a. 101.77 N

b. 63.59 N

c. 161.81 N

Explanation:

A p E x

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