The elastic potential energy stored in the stretched spring is 1 J.
<h3>What is Hooke's law?</h3>
Hooke's law states that; provided the elastic limit is not exceeded, the extension of the spring is directly proportional to the force on the spring.
Given that;
Force on the spring = 350 Newton
Distance stretched = 7 centimeters or 0.07 m
Hence;
F = ke
k = F/e = 350 Newton/0.07 m = 5000 N/m
Work done in stretching a spring = 1/2ke^2
= 0.5 × 5000 × (2 × 10^-2)^2 =1 J
Learn more about elastic potential energy: brainly.com/question/156316
Answer: D. the distance between the highest points of consecutive waves
Explanation:
The wavelength of a wave is defined as the <em>distance traveled by a periodic perturbation that propagates through a medium in a given time interval</em>. It is usually represented by
and can be calculated if the frequency of the wave is known, since there is an inverse relationship between both.
In the specific case of a periodic sine wave (which is the way in which a wave is usually represented graphically) the wavelength can be determined as the distance between two consecutive maxima of the disturbance.
Therefore, the correct option is D.
If the acceleration is constant, and the starting velocity is zero, the relationship between the acceleration of a falling body (a), the time it takes to fall (t), and instantaneous velocity when it hits the ground (v) is:
the general equation of acceleration is:
vf = vi + at
assuming the initial velocity (vi) is zero, the equation becomes:
vf = at
v = at
Answer: w = 200N
Explanation:
w = mg
m = 20kg
g = 10m/s^ (approximately)
w = 20kg . 10m/s^
w = 200N