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Otrada [13]
3 years ago
11

In outer space a rock of mass 12 kg is acted on by a constant net force 21, −11, 44 N during a 4 s time interval. At the end of

this time interval the rock has a velocity of 107, 81, 104 m/s. What was the rock's velocity at the beginning of the time interval?
Physics
1 answer:
Luda [366]3 years ago
6 0

Answer:

(100,84.67,89.33) m/s

Explanation:

From Newton's second law,

Impulse = Final momentum- initial momentum.

I = Mf-Mi.............. Equation 1

make Mi the subject of the equation

Mi = Mf-I............ Equation 2

Where I = Impulse. Mf = final momentum, Mi = initial momentum.

But

I = Ft.................... Equation 3

Where F = Force, T = time

Given: F = (21,-11,44) N, t = 4 s.

I = 4(21,-11,44)

I = (84,-44,176) N.s

Also,

Mf = mVf................ Equation 4

Where m = mass, Vf = Final velocity

Given: m = 12 g, Vf = (107,81,104) m/s.

Substitute into equation 4

Mf = 12(107,81,104)

Mf = (1284,972,1248) kgm/s.

Substitute the value of I and Mf into equation 2

Mi = (1284,972,1248)-(84,-44,176)

Mi = (1200,1016,1072) kgm/s

Also,

Mi = mVi

Where Vi = Initial velocity.

make Vi The subject of the equation

Vi = Mi/m..........................  Equation 5

Given: m = 12 kg, Mi = (1200,1016,1072) kgm/s

Substitute into equation 5

Vi = (1200,1016,1072)/12

Vi = (100,84.67,89.33) m/s

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if you were to increase either mass or speed by a unit of 1 in a joules calculation, which would give you more energy?
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A 0.40-kg cart with charge 4.0 x 10-5 C starts at rest on a horizontal frictionless surface 0.50 m from a fixed object with char
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Answer:

26.82m/s

Explanation:

Given

Mass = m= 0.4kg

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First, we'll calculate the initial energy (E)

E = Potential Energy

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Energy is then calculated by;

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0.2v² = 143.85

v² = 143.85/0.2

v² = 719.25

v = √719.25

v = 26.81883666380777

v = 26.82m/s

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