Answer:
V=21.0211m/s
Explanation:
Use V=vi+at
So, V=17.46m/s+(1.49m/
)(2.39s)= 21.0211m/s
Answer:
a)
, b) 
Explanation:
a) The system ice cube-spring is modelled by means of the Principle of Energy Conservation. Let assume that height at the bottom is zero:





b) The distance travelled by the ice cube is:


I believe the answer is A) Less work in less time.
Answer:
The resonant frequency of this circuit is 14.5 kHz.
Explanation:
Given that,
Inductance of a parallel LCR circuit, 
Capacitance of parallel LCR circuit, 
At resonance the inductive reactance becomes equal to the capacitive reactance. The resonant frequency is given by :



or
f = 14.5 kHz
So, the resonant frequency of this circuit is 14.5 kHz. Hence, this is the required solution.
Answer:
I'm pretty sure its B and C
Explanation:
B bc the weight is gravitational pull x mass so when the object has same mass the weight is smaller on moon
C bc mass is the same - you can't change it