Question

The coil has a radius of 8 cm and 110 turns. While moving the magnet closer towards the coil, at a certain point in time, the voltage meter shows -310 mV. What is the magnitude of the rate of change of the flux through the coil?

Answer 1

Answer:

The magnitude of the rate of change of the flux through the coil is 2.82 x 10⁻³ T.m²/s

Explanation:

Given;

radius of coil, r = 8 cm = 0.08 m

number of turns of the coil, N = 110 turns

the induced emf through the coil, E = -310mV

The induced emf through the coil is given by;

$E = - N\frac{d \phi}{dt} \\\\\frac{d \phi}{dt} = \frac{E}{-N}$

Where;

dФ/dt is the magnitude of the rate of change of the flux through the coil

$\frac{d\phi}{dt} = \frac{-0.31}{110} \\\\\frac{d\phi}{dt} =2.82*10^{-3} \ T.m^2/s$

Therefore, the magnitude of the rate of change of the flux through the coil is 2.82 x 10⁻³ T.m²/s