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Lena [83]
3 years ago
7

A 4.9 A current is set up in a circuit for 5.4 min by a rechargeable battery with a 6.0 V emf. By how much is the chemical energ

y of the battery reduced?
Physics
1 answer:
masha68 [24]3 years ago
4 0

Answer:

E =9525.6 J        

Explanation:

Given that

Current ,I = 4.9 A

time ,t = 5.4 min

Voltage difference ,ΔV = 6 V

energy delivered by battery in time t is given as

E=V I t

where V is voltage, I is the current and t is the time.

now putting the values in above equation

E= 6 x 4.9 x 5.4 x 60  J   ( 1 min = 60 s , 5.4 min  = 5.4 x 60 s)

E =9525.6 J

Therefore the energy reduced will be 9525.6 J

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What is the relation between Physical states of solution and solvent
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Explanation:

The solute does not have to be in the same physical state as the solvent, but the physical state of the solvent usually determines the state of the solution. As long as the solute and solvent combine to give a homogeneous solution, the solute is said to be soluble in the solvent.

4 0
2 years ago
You're using a monochromatic beam of light with wavelength 500 nm in an interferometer. What is the miminum distance you would n
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Answer:

Minimum distance needed to move one of the mirrors = 125 nm

Explanation:

Constructive interference occurs when the maxima (trough or crest) of two waves that are in phase add together so that the amplitude of the resulting wave is equal to the sum of the individual amplitudes.

Destructive interference occurs when the maxima (trough or crest) of two waves that are out of phase by 180⁰ or half a wavelength combine to produce a smaller amplitude than the individual amplitudes that combine. It can even produce a wave of zero amplitude.

Since the spot of constructive interference has been changed to destructive interference, Path difference = Wavelength/2

Path difference = 500nm/2 = 250 nm

Path difference = 250 * 10⁻⁹ m

Since there are two interferometer's mirrors and only one is moved, the minimum distance will be a half of the path difference.

That is, minimum distance = (path difference)/2

Minimum distance = (250 * 10⁻⁹)/2

Minimum distance = 125 * 10⁻⁹ m

Minimum distance = 125 nm

5 0
3 years ago
In a transformer a 120 volt dc Primary of 500 turns is connected to a secondary of 75 turns. What is the Induced voltage in the
oee [108]

Answer:

The induced voltage in the Secondary is 18 volt.

Explanation:

Given that,

Voltage = 120 volt

Number of turns in primary = 500

Number of turns in secondary = 75

We need to calculate the induced voltage in the Secondary

Using relation number of turns and voltage in primary and secondary

\dfrac{V_{p}}{V_{s}}=\dfrac{N_{p}}{N_{s}}

Where, N_{p} = Number of primary coil

N_{s} = Number of  secondary  coil

V_{p} = Voltage of primary coil

V_{p} = Voltage of primary coil

Put the value into the formula

\dfrac{120}{V_{s}}=\dfrac{500}{75}

V_{s}=\dfrac{120\times75}{500}

V_{s}=18\ Volt

Hence, The induced voltage in the Secondary is 18 volt.

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Which of the following absorbs the MOST heat energy?
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Darker is warmer C. Black objects.
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