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tester [92]
3 years ago
6

Explain How can you tell that river water is suspension ?

Physics
1 answer:
andreev551 [17]3 years ago
7 0

Answer:

Streams need vitality to move material, and levels of vitality change as the waterway moves from source to mouth.  

At the point when vitality levels are high, huge rocks and stones can be moved. Vitality levels are generally higher close to a waterway's source, when its course is steep and its valley slender. Vitality levels rise considerably higher in the midst of flood.  

At the point when vitality levels are low, just little particles can be moved (assuming any). Vitality levels are most reduced when speed drops as a waterway enters a lake or ocean (at the mouth).

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8. (Liquids, Gas) have no definite shape, and no definite volume.<br> A)Liquid<br> B)Gas
Fynjy0 [20]
B. gas has no definite shape or volume. liquid has definite volume but no definite shape
4 0
2 years ago
If a car has a momentum of 2.04 x 104 kgm/s and a velocity of 18 m/s, what is its mass?
muminat

Answer:

Mass = 1133.33 kg (Approx.)

Explanation:

Given:

Momentum = 2.04 x 10⁴ kg[m/s]

Velocity = 18 m/s

Find:

Mass

Computation:

Mass = Momentum / Velocity

Mass = [2.04 x 10⁴] / 18

Mass = 1133.33 kg (Approx.)

5 0
2 years ago
A 1.0-m long wire is carrying a certain amount of current. The wire is placed perpendicular to a magnetic field of strength 0.20
Marysya12 [62]

For a current-carrying wire running perpendicular to a magnetic field, the magnetic force acting on the wire is given by:

F = ILB

F = magnetic force, I = current, L = wire length, B = magnetic field strength

Given values:

F = 0.60N, L = 1.0m, B = 0.20T

Plug in and solve for I:

0.60 = I(1.0)(0.20)

I = 3.0A

5 0
3 years ago
A "spherical capacitor" is constructed of two thin, concentric spherical shells of conducting material. Let a be the radius of t
Shalnov [3]

Answer:

C=\frac{ab}{k(b-a)}

Explanation:

We can assume this problem as two concentric spherical metals with opposite charges.

We have also to take into account the formulas for the electric field and the capacitance. Hence we have

C=\frac{Q}{V}\\\\E=k\frac{Q}{r^2}\\

Where k is the Coulomb's constant. Furthermore, by taking into account the expression for the potential and by integrating

dV=Edr\\\\V=\int_{R_1}^{R_2}Edr=-\int_{R_1}^{R_2}\frac{kQ}{r^2}dr\\\\V=kQ[\frac{1}{R_2}-\frac{1}{R_1}]

Hence, the capacitance is

C=\frac{1}{k[\frac{1}{R_2}-\frac{1}{R_1}]}

but R1=a and R2=b

C=\frac{ab}{k(b-a)}

HOPE THIS HELPS!!

3 0
3 years ago
Read 2 more answers
5. If a spring with a 40 N/m spring constant is used to push a 10 kg ball to a speed of 2 m/s,
kolbaska11 [484]

By compressing the spring a distance <em>x</em> (in m), you are storing 1/2 <em>k</em> <em>x</em> ² (in J) of potential energy, which is converted completely into kinetic energy 1/2 <em>m v</em> ², where

• <em>k</em> = 40 N/m = spring constant

• <em>m</em> = 10 kg = mass of the ball

• <em>v</em> = 2 m/s = ball's speed (at the moment the spring returns to its equilibrium point)

So we have

1/2 <em>k</em> <em>x</em> ² = 1/2 <em>m</em> <em>v</em> ²

<em>x</em> = √(<em>m</em>/<em>k</em> <em>v</em> ²) = √((10 kg) / (40 N/m) (2 m/s)²) = 1 m

3 0
2 years ago
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