imagine a bouncing ball that does not lose any energy as it bounces. could it ever bounce to a greater height than it was droppe
d from? explain your answer
2 answers:
Answer:
No, due to conservation of energy, the bouncing ball would need to create energy in order to bounce higher.
Explanation:
The question says that the ball was dropped, so we suppose that it will start at an initial velocity of zero. (If the ball was tossed, then it's initial velocity would be greater than zero and it would bounce accordingly, but it would never bounce higher than it's maximum height)
Due to conservation of energy, the energy of the ball will remain the same throughout its trip. As the ball travels down to the ground, its potential energy decreases while its kinetic energy will increase, its sum will remain constant. When the ball hits the ground, it will have its maximum kinetic energy, which is equal to its potential energy (the energy the ball started with). The energy is transmited to the ground and back to the ball (supposing the bounce is completely elastic and no energy was lost as heat or vibration).
So the ball starts its way back up. The height it can reach will depend on its potential energy, since energy remains constant (energy is not created nor destroyed), the ball can only get as high as it was originaly dropped from sine its mass and the acceleration of gravity remains constant.
Take a look at the uploaded diagram which represents the given situation.
You might be interested in
The final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.
To find the answer, we need to know about the thermodynamic processes.
<h3>How to find the final temperature of the gas?</h3>- Any processes which produce change in the thermodynamic coordinates of a system is called thermodynamic processes.
- In the question, it is given that, the tank is rigid and non-conducting, thus, dQ=0.
- The membrane is raptured without applying any external force, thus, dW=0.
- We have the first law of thermodynamic expression as,
- Here it is zero.
,
- As we know that,
- Thus, the final temperature of the system will be equal to the initial temperature,
- We found that the process is isothermal,
- Thus, the work done will be,
Where, R is the universal gas constant.
<h3>What is a reversible process?</h3>- Any process which can be made to proceed in the reverse direction is called reversible process.
- During which, the system passes through exactly the same states as in the direct process.
Thus, we can conclude that, the final temperature of the system will be equal to the initial temperature, and which is 373K. The work done by the system is 409.8R Joules.
Learn more about thermodynamic processes here:
#SPJ1
Answer:
I=2 kg.m/s
Explanation:
The impulse is defined as the change of momentum:
We took the final velocity as negative since it is going on the opposite direction of the intial motion of the ball.
Answer:
Zero
Explanation:
Given the equation of an ellipse:
The eccentrity of an ellipse is given by:
For a circle, we have
Therefore the eccentricity of a circle is