Explanation:
perturbateur ( le temps, le lieu, les personnages[description], la victime, l'enqueteur )
les peripeties
le denouement
Answer:
100 cm
Explanation:
...........................
Answer:
Explanation:
First of all,we need to know what kind of research and how important it is before determining which computation method to use .
Then compare end result of research and cost of expensive methods .
Then we should opt for the best expensive method to be used for the given application.
Answer:
the critical flaw length is 10.06 mm
Explanation:
Given the data in the question;
plane strain fracture toughness = 92 Mpa√m
yield strength σ = 900 Mpa
design stress is one-half of the yield strength ( 900 Mpa / 2 ) 450 Mpa
Y = 1.15
we know that;
Critical crack length = 1/π( / Yσ )²
we substitute
= 1/π( 92 Mpa√m / (1.15 × 450 Mpa )²
= 1/π( 92 Mpa√m / (517.5 Mpa )²
= 1/π( 0.177777 )²
= 1/π( 0.03160466 )
= 0.01006 m = 10.06 mm
Therefore, the critical flaw length is 10.06 mm
{ = ( 10.06 mm ) > 3 mm
The critical flow is subject to detection