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Verizon [17]
3 years ago
12

Unscramble this caybnetruopergs * starts with "T" ends with "S" Please help me

Physics
1 answer:
dusya [7]3 years ago
8 0
Typebars
Turbocars
Teacups
Teapoys
Tourneys
Toecaps
Trepangs
Tabourers
Trouncers
Troupers
Terraces
Trances
Turbans
Toupees
Toucans
Sorry if this is not what you want me to do and I just threw a bunch of words at you. 
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Two cars are traveling along a straight road. Car A maintains a constant speed of 95 km/h and car B maintains a constant speed o
natulia [17]

Answer

given,

Speed of car A = 95 Km/h

                         = 95 x 0.278 = 26.41 m/s

Speed of Car B = 121 Km/h

                         = 121 x 0.278 = 33.64 m/s

Distance between Car A and B at t=0 = 41 Km

a) Distance travel by car B

   d = 26.41 t + 41000

speed of the car A = 33.64 m/s

distance = s x t

26.41 t + 41000 = 33.64 x t

7.23 t = 41000

t = 5670.82 s

time taken by Car B to cross Car A is equal to t = 5670.82 s

distance traveled by car A

D = s x t  = 26.41 x 5670.82 = 149766.25 m = 149.76 Km

b) distance travel by the car B in 30 s after overtaking car A

   D' = s x t = 33.64 x 30 = 1009.2 m = 1 Km  

8 0
3 years ago
At its Ames Research Center, NASA uses its large "20-G" centrifuge to test the effects of very large accelerations ("hypergravit
Over [174]

Answer:

v=32.9m/s

Explanation:

The acceleration needed to mantain a circular motion of radius r and speed v is given by the equation a=v^2/r

This is the centripetal acceleration. The person will feel what is called a centrifugal acceleration, of the same value, because he is not in an inertial frame (thus subject to fictitious forces, product of inertia).

We want to know the speed of his head when it is subject to 12.5 times the value of the acceleration of gravity while moving on a 8.84m radius circle, so we must do:

v=\sqrt{ar} = \sqrt{12.5gr}=\sqrt{(12.5)(9.8m/s)(8.84m)}=32.9m/s

7 0
3 years ago
7. A toy car of mass 1.2 kg is driving vertical circles inside a hollow cylinder of radius 2.0m. It is moving at a constant spee
wlad13 [49]

Answer:

a)

N_{top}=9.8N\\N_{bottom}=33.4N

b) v_{min}=4.4m/s

Explanation:

The net force on the car must produce the centripetal acceleration necessary to make this circle, which is a_{cp}=\frac{v^2}{R}. At the top of the circle, the normal force and the weight point downwards (like the centripetal force should), while at the bottom the normal force points upwards (like the centripetal force should) and the weight downwards, so we have (taking the upwards direction as positive):

-m\frac{v^2}{R}=-N_{top}-mg\\m\frac{v^2}{R}=N_{bottom}-mg

Which means:

N_{top}=m\frac{v^2}{R}-mg=(1.2kg)\frac{(6m/s)^2}{2m}-(1.2kg)(9.8m/s^2)=9.8N\\N_{bottom}=m\frac{v^2}{R}+mg=(1.2kg)\frac{(6m/s)^2}{2m}+(1.2kg)(9.8m/s^2)=33.4N

The limit for falling off would be N_{top}=0, so the minimum speed would be:

0=m\frac{v_{min}^2}{R}-mg\\v_{min}=\sqrt{Rg}=\sqrt{(2m)(9.8m/s^2)}=4.4m/s

3 0
3 years ago
A book falling to the floor is best described by: law one, law two, law three, or all three laws?
Law Incorporation [45]

The book falling to the floor is described by Newton's second law and Newton's third law

Explanation:

Newton's first law of motion states that:

"An object moving at constant velocity (or at rest) keeps moving at constant velocity (or will stay at rest) unless acted upon unbalanced, external forces"

For a book falling to the floor, there is an unbalanced force acting on it (the  force of gravity): therefore, we cannot apply Newton's first law.

Newton's second law of motion states that:

"The net force acting on an object is equal to the product between the object's mass, m, and its acceleration, a"

Mathematically:

F=ma

For the book falling to the floor, F is the force of gravity; therefore, we can apply Newton's second law, and in this case it tells us that the book has a non-zero acceleration during its fall.

In particular, the force of gravity is F=mg (where g is the acceleration due to gravity), so the acceleration of the book is

mg=ma\\a=g=9.8 m/s^2

Newton's third law of motion states that:

"When an object A exerts a force (action force) on an object B, then object B exerts an equal and opposite  force (reaction force) on object A".

In this case, the Earth is exerting a  force (the force of gravity) on the book during its fall: therefore, the book is also exerting a equal and opposite force (reaction force) on the Earth.

Learn more about Newton laws of motion:

brainly.com/question/3820012

brainly.com/question/11411375

#LearnwithBrainly

4 0
3 years ago
Non-living factors in an ecosystem are<br><br> biotic<br><br> abiotic<br><br> antibiotic
zaharov [31]

Answer:

Abiotic

Explanation:

The non living factors of the ecosystem which is essential for the survival of living factors of the ecosystem are abiotic factors.

Examples for abiotic factors include temperature, sunlight, water, wind etc....

3 0
3 years ago
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