Answer:
2.0*
Explanation:
Let us calculate total moles (air + CO)
moles (n) = PV /RT
P = 755 torr/760 = 0.9934 atm
V = 1.00 L
R = gas constant
T = 23°C + 273 = 296 K
So,
total moles (n) = 0.9934 x 1.00/0.0821 x 296 = 0.041 moles
mole fraction of CO = 8.1 x
moles of CO =8.1 x *0.041
=3.31 x moles
number of molecule of CO =3.31 x *(6.0233x )
= 2.0*
Answer:
The Force between the two charges is an attractive force of 16,000N
Explanation:
Expression for the electric force between the two charges is given by
F = (k*q1*q2) / r^2
Here, k = constant = 9 x 10^9 N*m^2 / C^2
q1 = - 2.0x10^-4C
q2 = + 8.0x10^-4C
r = 0.30 m
Substitute the given values in the above expression -
One charge is + and the other is a -, therefore the net force is an attractive force (opposites atract)
The attraction force is:
F= 9.0x10^9 * 2.0x10^-4 *8.0x10^-4 N/ 0.30^2
F= 16,000N
Answer:
F=-100N; a=1.3m/s^2
Explanation:
Force is being made by student, so wall counteracts that force by not moving so it is equally opposite.
Answer: The angle of inclination is nearly 30°
Explanation:
For a body on an inclined plane, the coefficient of friction between the body and the plane is equal to the ratio of the moving force applied to the body to the frictional force acting on the body.
If uK coefficient of friction;
Fm is the moving force
R is the normal reaction on the body
Mathematically uK = Fm/R
Fm = WSin(theta)
R = Wcos(theta)
uK = Wsin(theta)/Wcos(theta)
uK = tan(theta)
theta = arctan(uK)
If uK is 0.58
theta = arctan0.58
theta = 30°
The angle of the inclined will be 30°