<span>Electric field is a region around a charge in which the force of the charge can be exerted on the other charged particle. The force can be both inwards and outwards (repelling). Usually when it comes to a uniformly charged hollow metallic sphere the electric field associated is highest at outer surface of the sphere.</span>
Our eyes detect light only within a range of frequencies called visible light.
Answer:
acceleration a = 1,557 m/s²
Explanation:
Let's use the kinematic equations, the initial distance is 70 m (Xo = 70 m), also if the track is 2200m long or 100m long when clearing use a distance in the path of
X = 2200-100-70 = 2030 m
With this data let's calculate the acceleration
Vf² = Vo² + 2 a X
the jet leaves the rest (Vo=0=
a = Vf2 / 2X
a = 80 2/2 2030
a = 1,557 m/s²
Answer:
1/9
Explanation:
Sorry, I don't know if this is right, but here is what I did. We are ignoring potential energy because we assume that the student is walking and biking on level ground. Power = W/T, W = Mechanical Energy, or just Kinetic for this case. So 
, and 
. Ew = 
, and Eb =
. Put Ew over Eb. the 1/2's cancel, the m's cancel, and you are left with 
. Finally, this simplifies after cutting out the vw^2's to 1/9.
Answer: I think the answer is C
Larry is an architectural drafter Francis is an architect Meka is a construction manager and Lacey's interior designer.
