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adell [148]
3 years ago
8

We cab calculate work because we know the force and distance.what else would we need to know to calculate power

Physics
1 answer:
san4es73 [151]3 years ago
6 0

We would need to know how long it took to do the work.

Power = (work) / (time).

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What is the horsepower of a 1,500 kg car that can go to the top of a 360 m high hill in exactly 1 min?
Airida [17]

Answer:

W = m g h        work that must be done on car

P = W / t       power that must be input (in Watts)

P = m g h / t = 1500 kg * 9.8 m/s^2 * 360 m /  60 sec

P = 88,200 watts

P = 88,200 watts / 746 watts / hp = 118 hp

7 0
2 years ago
Which example best illustrates the transfer of energy between two waves?
FromTheMoon [43]

Answer:

A) A buoy rises in the water as a boat speeds past.

Explanation:

The passing boat transfers energy in the form of a wave. Other options illustrate other physics concepts like gravity (falling egg) or Newton's law (for every action, there is an equal and opposite reaction).

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3 years ago
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lubasha [3.4K]

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3 years ago
A disk of mass m and moment of inertia of I is spinning freely at 6.00 rad/s when a second identical disk, initially not spinnin
Nadusha1986 [10]

Answer:

The angular speed of the new system is 3\,\frac{rad}{s}.

Explanation:

Due to the absence of external forces between both disks, the Principle of Angular Momentum Conservation is observed. Since axes of rotation of each disk coincide with each other, the principle can be simplified into its scalar form. The magnitude of the Angular Momentum is equal to the product of the moment of inertial and angular speed. When both disks begin to rotate, moment of inertia is doubled and angular speed halved. That is:

I\cdot \omega_{o} = 2\cdot I \cdot \omega_{f}

Where:

I - Moment of inertia of a disk, measured in kilogram-square meter.

\omega_{o} - Initial angular speed, measured in radians per second.

\omega_{f} - Final angular speed, measured in radians per second.

This relationship is simplified and final angular speed can be determined in terms of initial angular speed:

\omega_{f} = \frac{1}{2}\cdot \omega_{o}

Given that \omega_{o} = 6\,\frac{rad}{s}, the angular speed of the new system is:

\omega_{f} = \frac{1}{2}\cdot \left(6\,\frac{rad}{s} \right)

\omega_{f} = 3\,\frac{rad}{s}

The angular speed of the new system is 3\,\frac{rad}{s}.

6 0
3 years ago
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