Answer:
Lens of the human Eye is a important and one of that most complex sense organ.
Explanation:
Lens of the human eye it helps that in visualizing light and color perception and objects , glance on the human eye structure and function.
Sense organs are much pretty similar to the camera they help us see the objects clear.
A human eye is the 2.3 cm in diameter and all filled some fluid, and there are following parts in eye:- cornea, Retina , Lens ,Pupil , optic nerves.
cornea :- the cornea is the first transparent part of is called cornea, enters the light through the cornea.
Retina :-it is light sensitive layer that consists of nerve cells,then transmitted to the brain through nerves.
Lens:- behind the pupil there is a transparent structure called lens,it shape focus light on the retina.
Pupil:-it control the value of light that enters the human eye.
Optic nerves is are the two types :- (1) cones (2) Rods .
Answer:
<em>Nitrogen</em>
Explanation:
<u>Composition of the Atmosphere</u>
The atmosphere contains several gases, most of them in small amounts, which may include some pollutants and greenhouse gases.
The most abundant gas in the atmosphere is nitrogen (78%), followed by oxygen (21%) as the second. The inert gas called Argon is the third most abundant gas in the atmosphere (less than 1%).
Finally, the fourth most abundant gas in Earth's atmosphere is Carbon dioxide
The difference in weight is due to the
displacement of water (the buoyancy of water is acting on the athlete thus
giving her smaller weight).<span>
The amount of weight displaced or the amount of buoyant force
is: </span>
Fb = 690 N - 48 N
Fb = 642 N
From newtons law, F = m*g. Using this formula, we
can calculate for the mass of water displaced:
m of water displaced = 642N / 9.8m/s^2
m of water displaced = 65.5 kg
Assuming a water density of 1 kg/L, and using the
formula volume = mass/density:
V of water displaced = 65.5kg / 1kg/L = 65.5 L
The volume of water displaced is equal to the
volume of athlete. Therefore:
V of athlete = 65.5 L
The mass of athlete can also be calculated using,
F = m*g
m of athlete = 690 N/ 9.8m/s^2
m of athlete = 70.41 kg
Knowing the volume and mass of athlete, her
average density is therefore:
average density = 70.41 kg / 65.5 L
<span>average density = 1.07 kg/L = 1.07 g/mL</span>
A believe that’s called a reference point.
