<span>A joule is equal to one watt per second and so we must find out how many seconds are in two hours.
A shortcut you can use is remove the zeros and multiplying the remaining numbers before adding the the zeros back to the total of your result
6 x 6 x 2 = 72 and thus
60 x 60 x 2 = 7200
72 x 15 = 1080 and thus
7200 x 1500 = 10800000 joules
one mega joule equals one million joules
So we can simplify things and say 10.8 MJ</span>
The horizontal force Superman must apply to throw the boulder is 3670N.
According to Newton's Second law of motion,
Force F = Mass m * Acceleration a
We know that Weight W = Mass m * Gravity g
Given,
Weight W = 2400 N
Acceleration a = 15 m/
Gravitational force g = 9.81 m/
W = m * g
Mass m = 2400 / 9.81 = 244.65 kg
Horizontal force F = 244.65 * 15 = 3669.7 N
Newton's Second law of motion states that acceleration of an object depends on force acting on the object and mass of the object.
Therefore the horizontal force Superman must apply to throw the boulder is 3670N.
To know more about horizontal force
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Answer:
It would show - New, waxing crescent, waxing half, waxing gibbous, full, waning gibbous, waning half, waning crescent phases just like moon.
Explanation: Geocentric model also known as geocentrism, gives the description of universe with Earth at the center. It is often exemplified by the Ptolemaic system. Under this system all the planets, stars, moon and the sun orbited the Earth. Ptolemaic order of spheres from Earth outward is Moon, Mercury, Venus, Sun, Mars. Jupiter, Saturn, Fixed stars, Primum Mobile. It was replaced by the heliocentric model where sun is at the center.
Answer: option 3 Ta < Tb = Tc < Td
Explanation:
Ta = mv²/r = mv²/r
Tb = m(2v)²/2r = (m)4v²/2r = 2mv²/r
Tc = (2m)v²/r = 2mv²/r
Td = (2m)(2v)²/r = (2m)4v²/r = 8mv²/r
velocity of plane with respect to air is given as 50 m/s towards west

now speed of the wind is given as 20 m/s south west

now the net speed with respect to ground is given as



so this speed with respect to ground is 65.7 m/s
this is greater than the speed with respect to air