Explanation:
Hybridization of O in 
So, water molecule has four hybrid orbitals.
Two hybrid orbitals form 2 sigma bond with two H atoms.
Remaining two hybrid orbitals are occupied by two lone pairs.
Because of lone pair-lone pair repulsion, shape of 
becomes bent.
Water molecule is polar because of difference in eletronegativities of O and H.
O is more electronegative as comapared to hydrogen. So bonding electrons get attracted towards O atom which results in the development of partial negative charge on O atom and partial positive charge on H atoms.
Because of development of partial negative and partial positive charge, water molecule becomes polar.
Answer:
The answers to the questions are given below.
Explanation:
According to Le Chatelier's principle, if an external constrain such as change in concentration, temperature or pressure is imposed on a chemical system in equilibrium, the equilibrium will shift in order to neutralize the effect.
A. Effective of removing ammonia, NH3.
N2(g) + 3H2(g) ⇌ 2NH3(g)
Removing NH3 from the reaction simply means we are left with more reactants and no product. Therefore, the reactant will react to produce the product. Hence, the equilibrium position will shift to the right.
2. Effect of removing H2
N2(g) + 3H2(g) ⇌ 2NH3(g)
Remoing H2 simply means we have more products and less reactant. Therefore, the product will be convert to reactant. Hence, the equilibrium position will shift to the left.
C. Effect of adding a catalyst.
N2(g) + 3H2(g) ⇌ 2NH3(g)
Catalyst does not affect the equilibrium position. It only creates an alternative path to arrive at the product within a short time. Hence, it has no effect.
Answer:
Insoluble in water:
Explanation:
Water turns out to be a good solvent for ionic substances, or in general, polarized covalent substances. On the other hand, it is not a good solvent for non-polar substances, these being the vast majority of covalent substances.
It doesn't because pepper does not dissolve
Answer:
I'm almost positive its d
Explanation:
hope this helps <3
