Answer:
Acceleration of the bags is 0.861 m/s²
Explanation:
Given:
Mass of the rock, m = 22.5 kg = mass of the food
Slope, Θ = 55.5°
Now, from the figure, we have
T - mgsinΘ = ma ...................(1)
'a' is the acceleration of the mass
where T is the tension
also for the second mass, we have
mg - T = ma
now substituting the value of T from the equation (1) we get
mg - (ma + mgsinΘ) = ma
or
mg(1 - sinΘ) = (m + m)a
or
a = 
on substituting the values we get
a = 
or
a = 0.861 m/s²
Hence, the acceleration of the bags is 0.861 m/s²
Answer:
A. Workdone by helium, W = -1.829KJ
B. Internal energy, DE = 25.271KJ
Explanation:
Workdone can be defined as the force moving through a distance. For a gaseous system, when the volume of the gas expands, the system is losing energy. Therefore,
W = -P*DV
Where P is the pressure in pascal
DV is the change in volume in m3
DV = Vfinal - Vinitial
= 23.70 - 5.30
= 18.4L
W = -(0.981 * 18.4)
= -18.0504L.atm
Converting L.atm to joule,
= -18.0504 * 101.325
= -1828.97J
= -1.829KJ
If the system loses heat, Q the rection occurring is Exothermic.
Heat is the transfer of energy from one system to another.
Q = mcDT
Where m is the mass of the system
C is the specific heat capacity
Q = 27.20KJ
Internal energy is the summation of the heat supplied to a system and the workdone by the system
DE = Q + W
DE = 27.10 + (-1.829)
= 25.27KJ
The choice of path should make no difference. The work should depend only on the end points and not on the route between them. But just to make sure, could we please have a look at the accompanying figure ?
