The speed of the sound in the xenon is 178 m/s. And the right option is b 178 m/s
<h3 /><h3>What is speed?</h3>
Speed can be defined as the ratio of the total distance traveled by a body to the total time taken.
To calculate the speed of the sound in the xenon, we use the formula below.
Formula:
- v = λf............. Equation 1
Where:
- v = Speed of the sound in xenon
- f = Frequency
- λ = Wavelength.
From the question,
Given:
- f = 440 Hz
- λ = 40.4 cm = 0.404 m
Substitute the values above into equation 1
- v = 440(0.404)
- v = 177.76 m/s.
- v ≈ 178 m/s
Hence, The speed of the sound in the xenon is 178 m/s. And the right option is b 178 m/s
Learn more about speed here: brainly.com/question/4931057
Acceleration = (0.2 x g) = 1.96m/sec^2.
<span>Accelerating force on 1kg. = (ma) = 1.96N. </span>
<span>1kg. has a weight (normal force) of 9.8N. </span>
<span>Coefficient µ = 1.96/9.8 = 0.2 minimum. </span>
<span>Coefficient is a ratio, so holds true for any value of mass to find accelerating force acting. </span>
<span>e.g. 75kg = (75 x g) = 735N. </span>
<span>Accelerating force = (735 x 0.2) = 147N</span>
Answer: The ball (option A)
Explanation: change in momentum is defined by the formulae m(v - u) where m = mass of object, v = final velocity and u = initial velocity.
For the ball, it hits the ground and bounces back with the same speed, that's final velocity equals initials (v = - u)
Change in momentum = m( -u- u) = m(-2u) = m(-2u) = -2mu
For the clay, it final velocity is zero since it sticks to the floor, hence (v =0)
m(v - u) = m(0 - u) = - mu.
-2mu (change in momentum from the ball) is greater than - mu ( change in momentum of clay)
Answer:
The minimum coefficient of friction is 0.544
Solution:
As per the question:
Radius of the curve, R = 48 m
Speed of the car, v = 16 m/s
To calculate the minimum coefficient of static friction:
The centrifugal force on the box is in the outward direction and is given by:
where
= coefficient of static friction
The net force on the box is zero, since, the box is stationary and is given by:
Answer:
Explanation:
Kinematics equation for first Object:
but:
The initial velocity is zero
it reach the water at in instant, t1, y(t)=0:
Kinematics equation for the second Object:
The initial velocity is zero
but:
it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s
The velocity is negative, because the object is thrown downwards
