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2 years ago

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The distribution circuit of a residential power line is operated at 2000 V rms. This voltage must be reduced to 240 V rms for us

e within the residences. If the secondary side of the transformer has 475 turns, how many turns are in the primary?

1 answer:

forsale [732]2 years ago

7 0

Answer:

$N_p\approx3958$

Explanation:

In an ideal transformer the relationship between the voltages is proportional to the ratio between the number of turns of the windings. Thus:

$\frac{V_p}{V_s} =\frac{N_p}{N_s}$

Where:

$V_p=Voltage\hspace{3}in\hspace{3}primary\hspace{3}coil$

$V_s=Voltage\hspace{3}in\hspace{3}secondary\hspace{3}coil$

$N_p=Turns\hspace{3}on\hspace{3}primary\hspace{3}coil$

$N_s=Turns\hspace{3}on\hspace{3}secondary\hspace{3}coil$

So, solving for $N_p$

$N_p=N_s*\frac{V_p}{V_s} =475*\frac{2000}{240} =3958.333333\approx3958$

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Answer:

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3 years ago

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Explanation:

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Read 2 more answers

A girl stands on the edge of a merry-go-round of radius 1.71 m. If the merry go round uniformly accerlerates from rest to 20 rpm

Mashutka [201]

Answer:

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3 years ago