Question

How many valence electrons are transferred from the calcium atom to iodine in the formation of the compound calcium iodide?

Answer 1

Answer:

Two electrons.

Explanation:

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or $1s^22s^22p^63s^23p^64s^2$

There are 2 valence electrons of Calcium.

Iodine is the element of seventeenth group and fifth period. The electronic configuration of Iodine is - 2, 8, 18, 18, 7 or $[Kr]4d^{10}5s^25p^5$

There are 7 valence electrons of iodine.

Calcium iodide, $CaI_2$ is formed when 2 valence electrons of calcium are loosed and they are gained by 2 atoms of iodine.