How many valence electrons are transferred from the calcium atom to iodine in the formation of the compound calcium iodide?
1 answer:
Answer:
Two electrons.
Explanation:
Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or
There are 2 valence electrons of Calcium.
Iodine is the element of seventeenth group and fifth period. The electronic configuration of Iodine is - 2, 8, 18, 18, 7 or
There are 7 valence electrons of iodine.
Calcium iodide, is formed when 2 valence electrons of calcium are loosed and they are gained by 2 atoms of iodine.
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Answer:
0.5 moles of LiOH will absorb 5.6 L of
Explanation:
According to law of conservation of mass, the sum of mass on the reactant side must be equal to the sum of mass on product side.
The balanced chemical equation is:
2 moles of LiOH absorb 1 mole of i.e. 22.4 Liters at STP
0.5 moles of LiOH absorb
=
0.5 moles of LiOH will absorb 5.6 L of
<u>Answer:</u> Carbon-carbon double bond is stronger and shorter than the single bond.
<u>Explanation:</u>
It is given that carbon-carbon double bond has greater energy than the carbon-carbon single bond.
Bond energy is directly proportional to the bond strength, which means that the double bond will have greater strength than single bond and triple bond has the greatest strength of all the bonds.
Bond energy is inversely proportional to the bond length of the carbon-carbon bond. This means that more is the bond energy, shorter will be the bond and vice-versa.
Hence, carbon-carbon double bond is stronger and shorter than the single bond.