Question

A body of rotational inertia 1.0 kg m2 is acted upon by a torque of 2.0 Nm. The angular acceleration of the body will be

Answer 1

Answer:

The angular acceleration is 2 rad/s².

Explanation:

Given that,

Rotational inertia = 1.0 kg m²

Torque = 2.0 Nm

We need to calculate the angular acceleration

Using formula of torque

$\tau=I\alpha$

$\alpha=\dfrac{\tau}{I}$

Where, I = moment of inertia

$\tau$ = torque

Put the value into the formula

$\alpha=\dfrac{2.0}{1.0}$

$\alpha=2\ rad/s^2$

Hence, The angular acceleration is 2 rad/s².