1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Inga [223]
3 years ago
8

(Almost) FREE POINTS!!!!! Hey there, Im writting a research paper, and I want to know if you think NASA is a waste of money or n

ot? Why do you think it is or isnt? Could the money be used better somewhere else? Im just looking for opinions with your facts to support,and no, Im not going to copy paste into my paper. Im looking for any points or reasons I may have missed. Thanks!
Engineering
2 answers:
alisha [4.7K]3 years ago
8 0

it depends on what ur using the money to do but in my opinion yes because it would make you have a better investment in space training or even air force training and would help your reputation.

hope this helps

tatuchka [14]3 years ago
3 0

Answer:

No I don't think NASA is a waste of time. I don't think its a waste of time because NASA is exploring what is beyond Earth and its important to know about Space.

Explanation:

You might be interested in
What is the maximum number of 12-2 with ground nonmetallic-sheathed cables permitted in an 18-cubic-inch device box if two singl
Novosadov [1.4K]

Answer:i think it is 35

Explanation:

i just guessed sorry im only in 5th grade

8 0
3 years ago
Read 2 more answers
The idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse
sertanlavr [38]

Answer:

T = 5416.67 N

T = -2083.5 N

T = 0

Explanation:

Forward thrust has positive values and reverse thrust has negative values.

part a

Flight speed u = ( 150 km / h ) / 3.6 = 41.67 km / s

The thrust force represents the horizontal or x-component of momentum equation:

T = flow(m_{exhaust})*(u_{exhaust} - u_{flight} )\\T = (50 kg/s ) * (150 - 41.67)\\\\T = 5416.67 N

Answer: The thrust force T = 5416.67 N

part b

Now the exhaust velocity is now vertical due to reverse thrust application, then it has a zero horizontal component, thus thrust equation is:

T = flow(m_{exhaust})*(u_{exhaust} - u_{flight} )\\T = (50 kg/s ) * (0 - 41.67)\\\\T = -2083.5 N

Answer: The thrust force T = -2083.5 N reverse direction

part c

Now the exhaust velocity and flight velocity is zero, then it has a zero horizontal component, thus thrust is also zero as there is no difference in two velocities in x direction.

Answer: T = 0 N

5 0
3 years ago
Tech A says that in some cases, the electronic brake control module can be programmed with a new tire size to restore proper ele
Vlad [161]

Answer:

Both Techs A and B

Explanation:

Electronic braking systems are controlled by the electronic brake control module. It is a microprocessor that processes information from wheel-speed sensors and the hydraulic brake system to determine when to release braking pressure at a wheel that's about to lock up and start skidding  and activates the anti lock braking system or traction system when it detects it is necessary.

Some electronic brake control modules can be programmed to the size of the vehicle's new tires to restore proper electronic brake control performance. While others may require replacing the module to match the module's programming to the installed tire size. So, both technicians A and B are correct.

3 0
3 years ago
A 11.5 nC charge is at x = 0cm and a -1.2 nC charge is at x = 3 cm ..At what position or positions on the x-axis is the electric
diamong [38]

Answer:

Explanation:

Given

q_1=11.5\ nC charge is placed at x=0\ cm

another charge of q_2=-1.2\ nC is at x=3\ cm

We know that Electric field due to positive charge is away  from it and Electric field due to negative charge is towards it.

so net electric field is zero somewhere beyond negatively charged particle

Electric Field due to q_2 at some distance r from it

E_2=\frac{kq_2}{r^2}

Now Electric Field due to q_1 is

E_1=\frac{kq_1}{(3+r)^2}

Now E_1+E_2=0

\frac{k\times 11.5}{(r+3)^2}\frac{k\times (-1.2)}{r^2}=0

\frac{3+r}{r}=(\frac{11.5}{1.2})^{0.5}

\frac{3+r}{r}=3.095

thus r=1.43\ cm

Thus Electric field is zero at some distance r=1.43 cm right of q_2

3 0
3 years ago
What different tests did the team perform to come up with a workable design?
I am Lyosha [343]
They ran different shapes and materials through a wind tunnel to see which shape and material would decrease energy output so that it takes in equal COthan it puts out.
5 0
3 years ago
Other questions:
  • Memory Question!
    7·1 answer
  • Model the real world idea of an Address. 123 Main Street Apt #2 Small Town, Iowa 55555 USA Write a class called Address, follow
    11·1 answer
  • Project 8:The Harris-Benedict equation estimates the number of calories your body needs to maintain your weight if you do no exe
    5·1 answer
  • DO NOW: Name the three main legal categories of ownership.
    12·1 answer
  • Shear strain can be expressed in units of either degrees or radians. a)True b)- False
    10·1 answer
  • At the grocery store you place a pumpkin with a mass of 12.5 lb on the produce spring scale. The spring in the scale operates su
    5·1 answer
  • 6. Question
    13·1 answer
  • Convert.46 to a percentage
    7·1 answer
  • The diameter of a cylindrical water tank is Do and its height is H. The tank is filled with water, which is open to the atmosphe
    11·1 answer
  • Entor" by
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!