Answer:
you can solve the rest of the equation. I only reduced it to that much to show you how to derive it
The mixture contains 62 % one isomer and 38 % the enantiomer.
Let’s say that the mixture contains 62 % of the (<em>R</em>)-isomer.
Then % (<em>S</em>) = 100 % -62 % = 38 %
ee = % (<em>R</em>) - % (<em>S</em>) = 62 % -38 % = 24 %
Answer:
False
Explanation:
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The most common sulfur ion has a charge of -2.