Temperature: Kelvin or degree Celsius; thermometer
Length: meter and its fractions and multiples; ruler
Volume: liter or cubic meter, mm, cm, km etc.; ruler for regular solids or empty spaces, graduated cylinder or kitchen measuring cup for liquids and irregular solids
Mass: kilogram and its multiples and fractions; balance with calibrated samples, or scale with knowledge of local gravity, or methods of applying known force and measuring acceleration
Answer: Question 1: Efficiency is 0.6944
Question 2: speed of similar pump is 2067rpm
Explanation:
Question 1:
Flow rate of pump 1 (Q1) = 300gpm
Flow rate of pump 2 (Q2) = 400gpm
Head of pump (H)= 55ft
Speed of pump1 (v1)= 1500rpm
Speed of pump2(v2) = ?
Diameter of impeller in pump 1= 15.5in = 0.3937m
Diameter of impeller in pump 2= 15in = 0.381
B.H.P= 6.0
Assuming cold water, S.G = 1.0
eff= (H x Q x S.G)/ 3960 x B.H.P
= (55x 300x 1)/3960x 6
= 0.6944
Question 2:
Q = A x V. (1)
A1 x v1 = A2 x V2. (2)
Since A1 = A2 = A ( since they are geometrically similar
A = Q1/V1 = Q2/V2. (3)
V1(m/s) = r x 2π x N(rpm)/60
= (0.3937x 2 x π x 1500)/2x 60
= 30.925m/s
Using equation (3)
V2 = (400 x 30.925)/300
= 41.2335m/s
To rpm:
N(rpm) = (60 x V(m/s))/2 x π x r
= (60 x 41.2335)/ 2× π × 0.1905
= 2067rpm.
The dimension of soccer field in ft is 377.315 ft long and 277.885 ft in width.
The dimension of soccer field in ft is 4527.78 in long and 3334.62 in in width.
As it is given that 1 m =3.281 ft
Therefore the length of the soccer field in ft is
115*3.281=377.315 ft
And width of the field is 85*3.281=277.885 ft
We know that 1 ft =12 in
Therefore the length of the soccer field in in is
377.315*12=4527.78 in
And width of the field is 277.885 *12=3334.62 in
Since the collision is inelastic, both vehicle will move with a common velocity of 2.5 m/s in south east direction after collision.
<h3>
Conservation of Linear Momentum</h3>
It states that, the sum of the momentum before collision is equal to the sum of the momentum after collision.
Given that a 7500 kg truck traveling at 5.0 m/s east collides with a 1500 kg car moving at 20 m/s in a direction 30° south of west. After collision, the two vehicles remain tangled together.
The given parameters are;
The formula to find the speed will be
M1U1 - M2U2 = (M1 + M2)V
7500 × 5 - 1500 × 10 = (7500 + 1500)V
37500 - 15000 = 9000V
22500 = 9000V
V = 22500/9000
V = 2.5 m/s
Therefore, the common speed will be 2.5 m/s and the direction of the car will be toward the south east.
Learn more about Collision here: brainly.com/question/7694106
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