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Alexxx [7]
3 years ago
14

U

Chemistry
1 answer:
Vlada [557]3 years ago
5 0

Answer:

7.86 moles of sodium chloride are produced.      

Explanation:

Given data:

Moles of chlorine = 3.93 mol

Amount of sodium = excess

Moles of sodium chloride formed = ?

Solution:

Chemical equation:

2Na + Cl₂     →     2NaCl

Now we will compare the moles of sodium chloride with chlorine.

                       Cl₂           :          NaCl

                          1            :            2

                        3.93        :           2×3.93 = 7.86

Chlorine is limiting reactant that's why we compare the NaCl with only number of mole of chlorine.

Thus, 7.86 moles of sodium chloride are produced.      

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\displaystyle \textbf{Percentage}\text{ Yield} = \frac{\textbf{Actual}\text{ Yield}}{\textbf{Theoretical}\text{ Yield}}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} = \frac{13.2}{17.632}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} =74.9\%.

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