Explanation:
Horizontal velocity = 49 m/s
Altitude, S = 66m
g= 9.81 m/s^2
weight W = 160N
mass m = w/g = 160/ 981 = 16.309 kg
when a object dropped from time time to reach the ground can be calculated from this equation.
S = Vot + 1/2 at^2
V_0 is the initial velocity in vertical direction. The plane moving horizontally an altitude of 66m it has only horizontal velocity.
The velocity V_0 in vertical direction is zero
S= 1/2 at^2
66=1/2 9.81 × t^2
t^2 = 13.455
t= 3.668 seconds (Time to hit the hay in ground)
Vertical velocity V = V _c + at (v_0 is zero, initial vertical velocity )
V = gt (acceleration is 'g')
V = 9.81 × 3.668
V = 35.98 m/s
The hay has two components of velocity when it reach the ground the horizontal velocity 49 m/s it will not change vertical velocity of 35.98 m/s
Resultant velocity can found by vector addition
velocity =
velocity = 60.78 m/s
The momentum of bale of hay = mv
= 16.309 × 60.78
The momentum of bale of hay =991.26 kg m/s