The kinetic energy (KE) is 250 J and the gravitational potential energy (GPE) is 392 J
When dealing with multiple forces acting on a body, it is advisable to draw a free-body diagram like that shown in the picture. There are four forces acting on the box: weight (W) pointing straight down, normal force perpendicular to the slope denoted as Fn, force used to push the box upwards along the slope and the frictional force acting opposite to the direction of motion of the box denoted as Ff. Frictional force is equal to coefficient of kinetic friction (μk) multiplied with Fn.
∑Fy = Fn - mgcos30° = 0
Fn = (50)(9.81)(cos 16) = 471.5 N
When in motion, the net force is equal to mass times acceleration according to Newton's 2nd Law of Motion:
Fnet = F - μk*Fn - mgsin30° = ma
250 - (0.2)(471.5 N) - (50)(sin 16°) = (50)(a)
a = 2.84 m/s²
Energy slowly leaks outward through the radiative diffusion of photons that repeatedly bounce off ions and electrons.
<h3>What is radiative diffusion?</h3>
A radiation zone is a layer of a star's core where energy is mostly carried toward the outside by radiative diffusion and thermal conduction rather than convection.
As photons, energy passes through the radiation zone as electromagnetic radiation.
The radiative diffusion of photons that repeatedly bounce off ions and electrons progressively drains energy outward.
Hence,radiative diffusion is correct answer.
To learn more about radiative diffusion refer:
brainly.com/question/3598352
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Answer:
The maximum height of the ball is 2 m.
Explanation:
Given that,
Mass of ball = 50 g
Height = 1.0 m
Angle = 30°
The equation is

We need to calculate the velocity
Using conservation of energy

Here, ball at rest so initial kinetic energy is zero and at the bottom the potential energy is zero

Put the value into the formula

Put the value into the formula




We need to calculate the maximum height of the ball
Using again conservation of energy

Here, h = y highest point
Put the value into the formula



Put the value of y in the given equation




Hence, The maximum height of the ball is 2 m.