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Juli2301 [7.4K]
3 years ago
7

If Earth had twice the mass it has now, how would the gravitational force between it and the Sun change?

Physics
1 answer:
zhenek [66]3 years ago
7 0

Answer:

a)The gravitational force would be twice as much as it is now

Explanation:

If the earth had twice its mass as it is now, the gravitational force between the sun and the earth would be twice as much as it is now.

According to Newton's law of universal gravitation "the gravitational force of attraction between bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them".

       F_{g}   = \frac{G m _{e} m _{s}  }{r^{2} }

G is the universal gravitation constant

m is the mass

r is the distance

let mass of sun  = s

     mass of earth  = e

 new mass of sun  = s

 new mass of sun  = 2e

input variables;

    F  = \frac{Gx e x s}{r^{2} }    ------ i

   F = \frac{G  x s x 2e}{r^{2} }    ------- ii

From the second equation;

      2F  = \frac{Gx e x s}{r^{2} }

      2F  = F

Therefore, the force will double.

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Dennis_Churaev [7]

As it was explained in the Introductory Article on the Electromagnetic Spectrum, electromagnetic radiation can be described as a stream of photons, each traveling in a wave-like pattern, carrying energy and moving at the speed of light. In that section, it was pointed out that the only difference between radio waves, visible light and gamma rays is the energy of the photons. Radio waves have photons with the lowest energies. Microwaves have a little more energy than radio waves. Infrared has still more, followed by visible, ultraviolet, X-rays and gamma rays.

That should be able to help answer your question :)
7 0
3 years ago
Write answers with significant figures:<br>a) 17.35 g +8.498 g​
Genrish500 [490]

Answer:

25.9 g

Explanation:

= 17.35

8.498

________+

= 25.848 g = 25.85 g = 25.9 g

*so sorry if wrong

6 0
3 years ago
5. What is the velocity of a Nolan Catholic football player if he runs 200.0 m in 24.0 s?
Degger [83]

Answer:

\boxed{ \bold{ \huge{ \boxed {\sf{8.33 \: m \:/s \: }}}}}

Explanation:

Distance travelled = 200 metre

Time taken = 24 second

Velocity = ?

<u>Finding </u><u>the</u><u> </u><u>velocity</u><u> </u>

\boxed{ \sf{velocity =  \frac{distance \: travelled \: }{time \: taken}}}

\dashrightarrow{ \sf{velocity =  \frac{200 \: m}{24 \: s} }}

\dashrightarrow{ \sf{velocity = 8.33 \: m/s}}

Hope I helped!

Best regards!

6 0
3 years ago
Determine the value of the resultant and its location from O.<br>see attach image.​
xxTIMURxx [149]

Answer:

Explanation:

In the x direction the force will be

½(-w₀)L/2 = -¼w₀L  

acting ⅔(L/2) = L/3 below the x axis.

In the y direction the force will be

½(-w₀)L + ½w₀L/2 = -¼w₀L  

the magnitude of the resultant will be

F = w₀L  √((-¼)² + (-¼)²) = w₀L√⅛

in the direction

θ = arctan(-¼w₀L / -¼w₀L) = 225°

to find the distance, we balance moments

(w₀L√⅛)[d] = ½(w₀)L[⅔L] + ¼w₀L[⅔L/2] - ¼w₀L[L - ⅓L/2]

     (√⅛)[d] = ½         [⅔L] + ¼      [⅔L/2] - ¼      [L - ⅓L/2]

     (√⅛)[d] = ½[⅔L] + ¼[⅔L/2] - ¼[L - ⅓L/2]

     (√⅛)[d] =      ⅓L  +    ⅟₁₂L     -  ¼L + ⅟₂₄L  

     (√⅛)[d] = 5L/24

               d = 5L/24 / (√⅛)

               d = 5√⅛L/3

8 0
3 years ago
When measuring an unknown voltage with an analog VOM, you should first
Soloha48 [4]
If you have no idea what the voltage is that you're about to measure,
then you should set the meter to the highest range before you connect
it to the two points in the circuit. 

Analog meters indicate the measurement by moving a physical needle
across a physical card with physical numbers printed on it.  If the unknown
voltage happens to be 100 times the full range to which the meter is set,
then the needle may find itself trying to move to a position that's 100 times
past the highest number on the meter's face.  You'll hear a soft 'twang',
followed by a louder 'CLICK'.  Then you'll wonder why the meter has no
needle on it, and then you'll walk over to the other side of the room and
pick up the needle off the floor, and then you'll probably put the needle
in your pocket.  That will end your voltage measurements for that day,
and certainly for that meter. 

Been there.
Done that.
8 0
3 years ago
Read 2 more answers
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