For a 650-kg satellite is in a circular orbit about Earth at a height above Earth equal to Earth’s mean radius, the resultant values are is mathematically given as
- V=5.59*10^3m/s
- T=3.98hours
- F=1.47*10^3N
<h3>What are the satellite’s orbital speed, the period of its revolution, and the gravitational force acting on it.?</h3>
Generally, the equation for satellite orbital speed is mathematically given as
a)
V=5.59*10^3m/s
b)
T=3.98hours
c)
Therefore
F=1.47*10^3N
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If a body is moving with uniform velocity, acceleration is zero. So net force acting on it will be also zero. But the body has energy due to its constant motion.
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Im gonna say it is answer A:) Hope this helps!
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