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Rzqust [24]
3 years ago
13

How many moles are in 75.0 grams of K2S?

Chemistry
1 answer:
notka56 [123]3 years ago
3 0

Answer:

0.6802 mol

Explanation:

1 grams K2S  = 0.00907 mol

0.00907 x 75 = 0.6802 mol

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The catalytic converter, a required component for automobile exhaust emission control systems, converts carbon monoxide into A.
Brums [2.3K]

Answer:

B. Carbon dioxide

Explanation:

A catalytic converter is designed and placed in the exhaust of most automobiles to remove harmful gases from escaping into the environment.

The converter uses palladium and platinum which are both catalyst to reduce harmful gases such as nitrogen oxide which causes acid rain, carbon monoxide which affects human haemoglobin and other hydrocarbons into less harmful ones.  

The catalytic converter helps to convert carbon monoxide, a product of incomplete combustion of hydrocarbons into less harmful carbondioxde. Carbon monoxide is a very toxic gas. It causes harm to both plants and animals as well.

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3 years ago
Describe what the greenhouse effect is and how it is caused on a molecular level.
Lina20 [59]

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The greenhouse affect is what traps the Sun’s heat or rays/ temperature in our atmosphere which causes our global warming

Explanation:

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3 years ago
The specific reaction rate of a reaction at 492k is 2.46 second inverse and at 528k 47.5 second inverse.find activation energy a
crimeas [40]

Answer:

Ea = 177x10³ J/mol

ko = 1.52x10^{19} J/mol

Explanation:

The specific reaction rate can be calculated by Arrhenius equation:

k = koxe^{-Ea/RT}

Where k0 is a constant, Ea is the activation energy, R is the gas constant, and T the temperature in Kelvin.

k depends on the temperature, so, we can divide the k of two different temperatures:

\frac{k1}{k2} = \frac{koxe^{-Ea/RT1}}{koxe^{-Ea/RT2}}

\frac{k1}{k2} = e^{-Ea/RT1 + Ea/RT2}

Applying natural logathim in both sides of the equations:

ln(k1/k2) = Ea/RT2 - Ea/RT1

ln(k1/k2) = (Ea/R)x(1/T2 - 1/T1)

R = 8.314 J/mol.K

ln(2.46/47.5) = (Ea/8.314)x(1/528 - 1/492)

ln(0.052) = (Ea/8.314)x(-1.38x10^{-4}

-1.67x10^{-5}xEa = -2.95

Ea = 177x10³ J/mol

To find ko, we just need to substitute Ea in one of the specific reaction rate equation:

k1 = koxe^{-Ea/RT1}

2.46 = koxe^{-177x10^3/8.314x492}

1.61x10^{-19}ko = 2.46

ko = 1.52x10^{19} J/mol

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3 years ago
When a 11.9 gram sample of copper metal is dropped into a glass of cold water, the temperature of the copper drops from 55°C to
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I need this one asap

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Which process is suitable to yield high quality ethanol greater than 95%​
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