Answer:
A. While inconsistent, his average of 1.0 kg made his results quite
accurate
Explanation:
Accuracy is how close the value you gain from test or observation compared with the real value. In this test, all tests relatively close to 1kg and the average of the test is 1kg so this tool can be considered quite accurate.
The precision determines how close the value of multiple repetitions of the test. In this case, the value varies from 0.8kg to 1.2kg. The highest value is about 50% higher than the lowest value, so the range is pretty far and the test can be considered not precise.
Hello!
The concentration of
hydronium ions is related to pH by the following simple equation:
![pH=-log[H_3O^{+}]](https://tex.z-dn.net/?f=pH%3D-log%5BH_3O%5E%7B%2B%7D%5D%20)
From this equation, you can see that as the hydronium concentration is higher, the pH will be lower.
The concentration of the OH⁻ ions is related to the pH by the following set of equations
![pOH=-log[OH^{-}] \\ pH=14-pOH](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E%7B-%7D%5D%20%5C%5C%20pH%3D14-pOH)
You can see that as the concentration of OH⁻ is higher, the pOH is lower and thus the pH is higher.
When the pH of the solution is less than 7, the solution is
acidic.When the pH of the solution is higher than 7, the solution is
basic.Have a nice day!
Answer:

Explanation:
There are two ways of looking at this problem. The first way, slightly more advanced, is to understand that the carbocation formed is an intermediate in this reaction: it is formed in one step and consumed in the subsequent step.
Secondly, we have hydroxide involved as our reactant, so it should be our second reactant in the second bimolecular step.
Thirdly, the product formed would be a combination of the anion and cation, one of our products, this means we have the following second step:

Another way is to verify this knowing that by adding all of the steps should yield a net equation, notice if we add the two steps together (reactants on one side and products on the other), we obtain:

Notice that the intermediate carbocation cancels out on both sides to yield the final net equation:

This means we have the correct second step.
<span>HF has a higher [OH-] than a solution of 1.0 M HCl. is the answer</span>