Answer:
Carbon dioxide
Explination:
I remember it from biology.
I hope this helps ^-^
#1
for the block of mass 5 kg normal force is given as
friction force is given as
Net force is given as
now we know that
#2
Normal force is given as
now we know that
as object moves with constant velocity
now for coefficient of friction we can use
#3
net force upwards is given as
mass is given as
now as per newton's law we can say
#4
As we know that when block is sliding on rough surface
part a)
net force = applied force - frictional force
part b)
for coefficient of friction we can use
here normal force is given as
now we have
#5
if an object is initially at rest and moves 20 m in 5 s
so we can use kinematics to find out the acceleration
now net force is given as
#6
an object travelling with speed 25 m/s comes to stop in 1.5 s
so here acceleration of object is given as
now the force is gievn as
Answer:
at its centre
Explanation:
The centre of gravity is a point inside the body where entire weight os the body is said to be concentrated. For geometrical symmetric bodies it lies at the geometric centre of the body.
The base ball is a spherical body, so its centre of gravity lies at its centre.
Answer:
a) Ktotal = 71.85 J
b) Ktotal = 71.85 J
Explanation:
a) The total kinetic energy is that of the total mass of the bicycle plus the rotational kinetic energy of the two wheels. The linear speed of the circumference of the wheels matches the forward speed of the bicycle, so their angular speed is
ω = v/r
The moment of inertia of one solid disk bicycle wheel is
I = 0.5*m₂*r²
And the rotational kinetic energy of one wheel is
Kr = 0.5*I*ω² = 0.5*(0.5*m₂*r²)*(v/r)² = 0.25*m₂*v²
The total kinetic energy is then that of the frame and wheels plus the rotational kinetic energy.
Ktotal = 0.5*(m₁ + 2*m₂)*v² + 2*(0.25*m₂*v²)
⇒ Ktotal = 0.5*v²*(m₁ + 3*m₂)
where
m₁ = 6.75 Kg
m₂ = 0.820 kg
v = 3.95 m/s
then
⇒ Ktotal = 0.5*(3.95 m/s)²*(6.75 Kg + 3*0.820 kg)
⇒ Ktotal = 71.85 J
b) We can apply the same equation obtained before
⇒ Ktotal = 0.5*v²*(m₁ + 3*m₂)
where
m₁ = 675 Kg
m₂ = 82.0 kg
v = 0.395 m/s
then
⇒ Ktotal = 0.5*(0.395 m/s)²*(675 Kg + 3*82 kg)
⇒ Ktotal = 71.85 J
