Using the pressure law (P1 x V1)/ T1 = (P2 x V2)/ T2 where P1= the initial pressure V1= initial volume T1= initial temperature and P2= the final pressure V2= the final volume T2 = the final temperature and temperature is always in kelvin
Answer:
540 J
Explanation:
U at top equals to K at bottom if it's an isolated system therefore U at top is equals to 540 J so we can assume that at 0m U=0 (mgh) therefore the box has gained some velocity due to the acceleration due to g and we can calculate it using 1/2mv²
C.0 because it didn't move<span />
Answer:
P₃ > P₁ > P₂
Explanation:
To rank pressure of the given situation
a) we know
Pressure at height h below
P = ρ g h
density of salt water, ρ = 1029 kg/m³
P₁ = 1029 x 10 x 0.2
P₁ = 2058 Pa
b) density of fresh water, ρ = 1000 kg/m³
P₂ = 1000 x 10 x 0.2
P₂ = 2000 Pa
c) density of mercury, ρ = 13593 kg/m³
P₃ = 13593 x 10 x 0.05
P₃ = 6796.5 Pa
Rank of Pressures from highest to lowest
P₃ > P₁ > P₂
