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Cerrena [4.2K]
3 years ago
11

M+e → M? Has M lost or gained an electron?

Chemistry
1 answer:
uranmaximum [27]3 years ago
6 0
It gained an electron.
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Which inquiry skill is based on identifying common features?
expeople1 [14]
<span>Classify is the answer hope this helps :)</span>
3 0
3 years ago
"what is the mole fraction of solute in a 3.87 m aqueous solution?"
sattari [20]

The mole fraction of solute in a 3.87 m aqueous solution is 0.0697

<h3> calculation</h3>

molality = moles of the solute/Kg of the solvent

3.87 m dissolve in 1 Kg of water= 1000g

find the moles of water= mass/molar mass

that is 1000 g/ 18 g/mol= 55.56 moles

mole of solute = 3.87 moles

mole fraction is = moles of solute/moles of solvent

that is 3.87/ 55.56 = 0.0697

5 0
3 years ago
Read 3 more answers
An isomer with a branched structure will require:
Contact [7]
The  branched  structure  isomer  will require   less  energy  to  melt  than the straight  chain  isomer

    explanation
Branched  structure  isomer    has  weak  intermolecular  forces  of attraction  as  compared  to  straight  chain  isomers.  In addition the  branched  isomer  has  a  low boiling point as  compared to  straight chain isomers. Since   boiling require  the of  the  intermolecular  forces tend to have  lower  boiling  point   than straight chain
8 0
4 years ago
Indicate the FULL NAME and TOTAL NUMBER of each element in the chemical formula provided. *
REY [17]

Answer:

4 lead  =  Pb

2 nitrogen = N

6 oxygen = O

Explanation:

Know the rules of multiplying wth perentheses.

- Hope that helped! Please let me know if you need further explanation.

6 0
3 years ago
Carvone is a substance that occurs in two forms having different arrangements of the atoms but the same molecular formula (c10h1
Korvikt [17]

The molecular mass of Carvone is calculated as;

                          =  12 (C)₁₀  +  1.008 (H)₁₄  +  16 (O)

                          =  120  +  14.112  +  16

                          =  150.112

%age of Carbon;

                          =  (120 ÷ 150.112) × 100

                          =  79.94 %

%age of Hydrogen;

                          =  (14.112 ÷ 150.112) × 100

                          =  9.40 %

%age of Oxygen;

                          =  (16 ÷ 150.112) × 100

                          =  10.65 %

7 0
3 years ago
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