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zheka24 [161]
4 years ago
8

Give the structure corresponding to the name (s)−3−iodo−2−methylnonane.

Chemistry
1 answer:
Morgarella [4.7K]4 years ago
7 0
The (s) in the chemical name of (s)-3-iodo-2-methylnonane indicates an S-configuration using the Cahn-Ingold-Prelog system of stereochemical nomenclature. The S-configuration means that an "imaginary" rotation from the highest priority substituent group to the lowest priority substituent group of the chiral center moves counterclockwise (to the left), provided that the lowest priority group is oriented "towards the back" (symbolized by dashed lines). 

The highest priority group (iodine in this case) is the one with the highest atomic number and the lowest priority (hydrogen in this case) is one with the lowest atomic number.

If the atoms directly beside the chiral center have the same atomic number (Carbon-2 and Carbon-4 in this case), the atoms next to them will be evaluated until a point of difference is found. Carbon-2 is connected to 2 other carbon atoms and 1 hydrogen atom, while Carbon-4 is connected to only 1 carbon atom and 2 hydrogen atoms. Thus, Carbon-2 has a higher priority, with the point of difference being the carbon atom of the methyl group attached to Carbon-2. Both Carbon-2 and Carbon-4 are connected to one carbon atom from the main nonane chain, but the other atoms connected to Carbon-4 are hydrogen atoms only. Carbon-2 has an extra carbon connected to it and carbon has a higher atomic number than hydrogen.

If there is no point of difference, the central atom is not chiral and cannot be named using the Cahn-Ingold-Prelog system. 

Thus, the structure of (s)-3-iodo-2-methylnonane is


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Explanation:

As we know that water freezes at 0ºC and vaporizes at 100ºC, we calculate the heat as follows:

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  • Processes of ice melting (at 0ºC): by using heat of fusion of ice (ΔH fus) multiplied by a conversor factor (1 mol H20= 18 g)⇒ ΔHfus x 1mol/18g
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A) Water at -25ºC is ice. Ice is heated from -25ºC to 0ºC, then it melts at 0ºC (ice became liquid water) and then liquid water is heated from 0ºC to 70ºC. T

This is the only process in with the heat is absorbed (not releases), so it cannot be the right answer, but we calculate the heat involved to practice:

Heat= (Sh ice x ΔT) + (ΔH fus x 1/18 g) + Sh liq x ΔT

Heat= (2.05 J/g ºC x (0ºC -(-25ºC) ) + (6.01 x 10³ J/mol x 1 mol/18 g) + (4.18 J/g ºC x (70ºC-0ºC)

Heat= 51.25 J + 333,8 J +292.6 J

Heat= 677.65 J (heat is absorbed)

B) Water is cooled from 13ºC to 0ºC, then it is freezed at 0ºC and then the ice is cooled from 0ºC to -2.6 ºC

Heat= (Sh liq x ΔT) + (-ΔH melt x 1/18 g) + (Sh ice x ΔT)

Heat= 4.18 J/ºC x (0ºC- 13ºC) + (-6.01 x 10³ J/mol x 1mol/18 g) + (2.05 J/ºC x (-2.5ºc - 0ºC)

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Heat= Sh liq x ΔT

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Heat = Sh vap x ΔT

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E) Vapor at 106ºC is cooled to 100ºC, then it condenses at 100ºC (convertion from gas to liquid), and liquid water is cooled from 100ºC to 88ºC.

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