Following reaction takes place between LiOH and HNO3
LiOH + HNO3 → LiNO3 + H2O
Thus, 1 mole of LiOH reacts with 1 mole of HNO3 to form 1 mole of LiNO3.
Now,
Number of millimoles of LiOH consumed = <span>36.90 X 0.100 = 3.690
</span>∴Number of millimoles of HNO3 present = 3.690
<span>
Now, Molarity of HNO3 = </span>

=

= 0.0738 M
Thus, <span>
molarity of the HNO3 solution is 0.0738 M</span>
Answer:
Alkane
Alkene
Alkyne
Explanation:
Alkane=1 bond (Saturated hydrocarbon)
Alkene= 2 bonds (Unsaturated hydrocarbon)
Alkyne= triple bonds (Unsaturated hydrocarbon)
Formula of Alkane = CnH2n+2
Formula of Alkene = CnH2n
Formula of Alkyne = CnH2n-2
Medical books would be the best because it is a valid resource
Molar mass:
Atomic mass O = 16.0 a.m.u
O₃ = 16.0 x 3 => 48.0 g/mol
Therefore:
1 mole O₃ --------------- 48.0 g
0.020 mole O₃ ---------- ??
0.020 x 48.0 / 1 =
0.96 / 1 => 0.96 g
hope this helps!
8A+2B——> 6C
since you multiply by a factor of 2 you do that to each letter
4*2=8
1*2=2
3*2=6